Aqueous solutions of sodium sulfide and copper(II) chloride are mixed together. Which statement is correct? a.Both NaCl and CuS will precipitate from solution b.No precipitate will form c.Only CuS will precipitate from solution d.Only NaCl will precipitate from solution

Answers

Answer 1
Answer:

C.Only CuS will precipitate from solution

Aqueous solutions of sodium sulfide and copper(II) chloride are mixed together.

  • According to question theEquation :

Na₂S(aq) + CuCl₂(aq) → Products

  • The complete balanced reaction is:

Na₂S(aq) + CuCl₂(aq) →  CuS(s) ↓ +  2NaCl(aq)

When the sulfide bond to the cation Cu²⁺ it makes a precipitate (s)

 

Thus,the correct answer is C.

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Answer 2
Answer:

Answer:

The correct state for the answer is c.

Only CuS will precipitate from solution

Explanation:

We analyse the compounds for the reaction and we write the equation:

Na₂S(aq) + CuCl₂(aq) → Products

For this case, the products are NaCl and CuS. The complete balanced reaction is:

Na₂S(aq) + CuCl₂(aq) →  CuS(s) ↓ +  2NaCl(aq)

When the sulfide bond to the cation Cu²⁺ it makes a precipitate (s)

Salts from chlorides are soluble except for the Ag⁺, Pb⁺ or Cu⁺

Salts from S⁻² which are soluble, are found in the group 2 of the Periodic Table (Ca²⁺, Ba²⁺, Mg²⁺)

The correct state for the answer is c.


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A 2.00 L container of gas has a pressure of 1.00 atm at 300 K. The temperature of the gas is halved to 150K, and the measured pressure of the same 2.00 Liter sample is 0.420 atm. Which of the following is the best explanation for these observations? A. Pressure is proportional to temperature for a fixed volume of gas. B. The molecules of the gas occupy a significant portion of the volume. C. The molecules of the gas have negligible volume of their own. D. The molecules have significant attractive forces at 150 K. E. The gas is closer to an ideal gas at 150 K.

Answers

The best explanation for the observation is that, the Pressure is proportional to temperature for a fixed volume of gas. (Option A)

From the question given above, the following data were obtained:

  • Initial volume (V₁) = 2 L
  • Initial pressure (P₁) = 1 atm
  • Initial temperature (T₁) = 300 K
  • Final temperature (T₂) = 150 K
  • Final volume (V₂) = 2 L = constant
  • Final pressure (P₂) = 0.420 atm

From the above, we can see that the volume is constant.

Applying the combine gas equation, we can conclude as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

V₁ = V₂

P₁ / T₁ = P₂ / T₂

P/T = constant

P = constant × T

Thus, we can conclude that the pressure is proportional to the temperature at constant volume. This simply implies that the pressure will increase if the temperature increase and it will also decrease if the temperature decreases.

The correct answer to the question is Option A.

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Answer:

A

Explanation:

PV=nRT

PV/nT

V/T -> (1)/(300)=(x)/(150)

               x=.420

You have a sample of gold that contains 0.2 moles of gold (Au). How many gold atoms are present in the sample. HINT: Gold atoms represents the number of particles."1.20 x 10^23 atoms

3.3 x 10^-25 atoms

1.01 x 10^-3 moles

Answers

Given:

n = 0.20 mol

Required:

N

Solution:

N = n × 6.02 × 10²³ atoms/mol

N = 0.2 mol × 6.02 × 10²³ atoms/mol

N = 1.20 × 10²³ atoms

Therefore, there are 1.20 × 10²³ gold atoms in 0.2 mol of a gold sample.

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1.01 x 10^-3 moles

A solution of NaOH has a concentration of 25.00% by mass. What mass of NaOH is present in 0.250 g of this solution? Use the periodic table in the toolbar if needed.

Answers

Answer : The mass of NaOH present in the solution is, 0.0625 grams

Explanation : Given,

Mass % = 25 %

Mass of solution = 0.250 g

Formula used :

Mass\%=\frac{\text{Mass of}NaOH}{\text{Mass of solution}}* 100

Now put all the given values in this formula, we get the mass of NaOH.

25=\frac{\text{Mass of}NaOH}{0.250g}* 100

\text{Mass of}NaOH=0.0625g

Therefore, the mass of NaOH present in the solution is, 0.0625 grams

The concentration of NaOH is 25.00% by mass, it means that 25.00% of the mass of the solution is of NaOH. Hence:

m_(NaOH)=25.00\%* m_(solution)\Longrightarrow m_(NaOH)=(25)/(100)* 0.250~g\iff\n\n\boxed{m_(NaOH)=0.0625~g}

How many molecules are in 2.50 moles of co2

Answers

Explanation:

There are 1.51 x 1024 molecules of carbon dioxide in 2.50 moles of carbon dioxide.

A 14 wt% solution of cacl2 (110.98 g/mol) has a density of 1.126 g/ml. what is the mass (in milligrams) of a 20.0-ml solution of 14.0 wt% cacl2?

Answers

Density = mass / volume

Thus, Mass of the solution can be expressed as:

Mass of solution = Density of solution × volume of solution

Given- Density of solution = 1.126 g/ml

volume of solution = 20.0 ml

∴ Mass of 14 wt% solution of CaCl2 = (1.126 g/ml) × (20 ml)

                                                           = 22.52 g

                                                           = 22520 mg

What type(s) of intermolecular forces exist between two molecules of 1-pentanol? (BLB Ch. 11)

Answers

Answer:

Hydrogen bonding

London dispersion forces

Explanation:

The most pronounced and consequential intermolecular forces at play has to be hydrogen bonding due to the dipole created between the oxygen and hydrogen in the hydroxyl group. And then to a lesser extent there are very weak London dispersion forces that are always going to be there in between any two molecules of any species.