The sixth graders at jenna's school got to visit either the science museum or the history museum. 32 students picked the science museum and 16 picked the history museum. What is the ratio of the number of sixth graders who visited the history museum to the number of sixth graders who visited the science museum?

Answers

Answer 1

Answer:

The ratio of the number of sixth graders who visited the history museum to the number of sixth graders who visited the science museum is 2 : 1.

What are ratio and proportion?

A ratio is a comparison between two similar quantities in simplest form.

Proportions are of two types one is the direct proportion in which if one quantity is increased by a constant k the other quantity will also be increased by the same constant k and vice versa.

In the case of inverse proportion if one quantity is increased by a constant k the quantity will decrease by the same constant k and vice versa.

Given, The sixth graders at Jenna's school got to visit either the science museum or the history museum. 32 students picked the science museum and 16 picked the history museum.

∴ The ratio of the number of sixth graders who visited the history museum to the number of sixth graders who visited the science museum

History museum : Science museum = 32 : 16.

History museum : Science museum = 2 : 1.

For every 2 students go to the science museum, 1 student goes to the history museum.

learn more about proportion here :

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Answer 2

Answer:

Answer:

The ratio is 16:32 or 1:2. this is because 16 times 2 is 32.

Hope this helped! Please mark me brainliest if I am correct! Thank you and have a great day!

Step-by-step explanation:

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Let C be between D and E. Use the segment addition postulate to solve for m. DC = 6m − 21 CE = 7m − 18 DE = 65 a. –3 c. 13 b. 5 d. 8

Answers

D-C-E

DC = 6m - 21
CE = 7m - 18
DE = 65

DC + CE = DE
6m - 21 + 7m - 18 = 65
13m - 39 = 65
13m = 65 + 39
13m = 104
m = 104/13
m = 8

DC = 6m - 21 = 6(8) - 21 = 48 - 21 = 27
CE = 7m - 18 = 7(8) - 18 = 56 - 18 = 38

Which two numbers add up to 6 and muliply to -126

Answers

xy=-126
x+y=6
minus x

y=6-x
sub
x(6-x)=-126
6x-x^2=-126
minus (6x-x^2) both sides
0=x^2-6x-126

in form
ax^2+bx+c=0
x= $\frac{ -b+/-\sqrt{b^(2)-4ac} }{2a}$

a=1
b=-6
c=-126

x= $\frac{ -(-6)+/-\sqrt{(-6)^(2)-4(1)(-126)} }{2(1)}$
x= $( 6+/-√(36+504) )/(2)$
x= $( 6+/-√(540) )/(2)$
x= $( 6+/-6√(150) )/(2)$
x= $3+/-3√(150)$

the numbers are
$3+3√(150)$ and $3-3√(150)$

What value or values of x satisfy 2|x+5.3|=4.2a. x can only equal –3.2.
b. x can only equal 7.4.
c. x can equal –3.2 or –7.4.
d. x can equal –3.2 or 7.4.