The diffuser in a jet engine is designed to decrease the kinetic energy of the air entering the engine compressor without any work or heat interactions. Calculate the velocity at the exit of a diffuser when air at 100 kPa and 30°C enters it with a velocity of 357 m/s and the exit state is 200 kPa and 90°C. The specific heat of air at the average temperature of 60°C = 333 K is cp = 1.007 kJ/kg·K.
Answers
Answer:
81.29 m/s
Explanation:
Given:
60°C = 333 K is cp = 1.007 kJ/kg·K.
at air inlet:
Pressure = 100 kPa
Temperature = 30°C
Velocity = 357 m/s
at air outlet:
Pressure = 200kPa
Temperature = 90°C
We can define the energy balance as:
-
= Δ
= 0
therefore, =
m + m
=m
+
(taking m common and cancelling it)
4 +
=
+
The velocity at the exit of a diffuser:
= [
+ 2
(
-
)
= [
+ 2 x 1000 x 1.007 x (30-90)
= 81.29 m/s
therefore, the velocity at the exit of a diffuser is 81.29 m/s
Answer:
Exit velocity = 498.3m/s
Explanation:
The energy balance for the system is given by:
Ein - Eout = ◇Esystem
Ein = Eout
Therefore
m' (h1 + V1^2/2) = m' (h2 + V2^2/2)
h1 + V1^2/2 = h2 + V2^2/2
The exit velocity will be:
V2 = [V1^2 + 2(h1 - h2)^0.5 = [V1^2 + 2(cp(T1 - T2)]^0.5
But cp = 1.007kJ/kg
V2 = [(357)^2 + 2(1.007)(90-30)(1000m^2/s^2)]^0.5
V2 = [127449 + 120840]^0.5
V2 = [248289]^0.5
V2 = 498.3m/s
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A child's toy consists of a spherical object of mass 50 g attached to a spring. One end of the spring is fixed to the side of the baby's crib so that when the baby pulls on the toy and lets go, the object oscillates horizontally with a simple harmonic motion. The amplitude of the oscillation is 6 cm and the maximum velocity achieved by the toy is 3.2 m/s . What is the kinetic energy K of the toy when the spring is compressed 5.1 cm from its equilibrium position?Problem-Solving Strategy: Simple Harmonic Motion II: EnergyThe energy equation, E=12mvx2+12kx2=12kA2, is a useful alternative relationship between velocity and position, especially when energy quantities are also required. If the problem involves a relationship among position, velocity, and acceleration without reference to time, it is usually easier to use the equation for simple harmonic motion, ax=d2xdt2=−kmx (from Newton’s second law) or the energy equation above (from energy conservation) than to use the general expressions for x, vx, and ax as functions of time. Because the energy equation involves x2 and vx2, it cannot tell you the sign of x or of vx; you have to infer the sign from the situation. For instance, if the body is moving from the equilibrium position toward the point of greatest positive displacement, then x is positive and vx is positive.IDENTIFY the relevant conceptsEnergy quantities are required in this problem, therefore it is appropriate to use the energy equation for simple harmonic motion.SET UP the problem using the following stepsPart AThe following is a list of quantities that describe specific properties of the toy. Identify which of these quantities are known in this problem.Select all that apply.Select all that apply.maximum velocity vmaxamplitude Aforce constant kmass mtotal energy Epotential energy U at xkinetic energy K at xposition x from equilibriumPart BWhat is the kinetic energy of the object on the spring when the spring is compressed 5.1 cm from its equilibrium position?Part CWhat is the potential energy U of the toy when the spring is compressed 5.1 cm from its equilibrium position?
Answers
Answer:
d = 235 nm.
Explanation:
Let the layer be of glass. Refractive index of glass μ = 1.5. Let the required thickness be d.
For minimum reflection , that is destructive interference in thin films , the condition is
2μd = λ ( for first order)
d = 705 / 2 x 1.5 = 235 nm [ λ =705 nm ]
Answers
Hope that helped =)
Answers
Use the formula:
F = kq1q2/r^2
F = force = 8.3x10^-4N
q1, q2 = charges
r = separatioon
k = constant = 9x10^9 in MKS units
so we have
r = sqrt[k q1 q2/F]
r = sqrt[9x10^9*(-14)x10^-9 * (-6)x10^-9 / 8.3x10^-4 ]
r = 0.0302 m
So the distance between spheres is 0.0302 m
Answers
Principles of relative dating
Uniformitarianism. ...
Intrusive relationships. ...
Cross-cutting relationships. ...
Inclusions and components. ...
Original horizontality. ...
Superposition. ...
Faunal succession. ...
Lateral continuity.
https://en.wikipedia.org/wiki/Relative_dating
b. ion.
c. electron.
d. neutron. user: which sentence best describes mass movement?
a. the steady pace of air bouncing off a mountain
b. the downhill movement of animals due to heavy snow in their normal home
c. the movement of particles within an atom
d. the downhill flow of soil and rock resulting from gravity
Answers
The answer would be B. Ion.