Find the equation of a line perpendicular to y - 12 = 2x – 8 that passes through the point (2, 3). (answer in slope-intercept form)

Step-by-step explanation:

The p-value for the given test is 0.0901.

Given that, a pharmaceutical manufacturer is concerned that the impurity concentration in pills should not exceed 3%.

What is a standard deviation?

Standard deviation is the degree of dispersion or the scatter of the data points relative to its mean, in descriptive statistics.

Given, Mean = 3.07, μ=3%, σ =0.4% and n=64.

Hypothesis test ;μ=3 and ;μ>3

We need to test the null hypothesis against the alternative hypothesis, we reject the null hypothesis and accept the alternative hypothesis.

When x>x critical

x critical = μ+Z+σ

Z = (x-μ)/(σ/√n)

= (3.07-3)/(0.4/√64)

= (0.07)/0.05

= 1.4

α = 5 and = 1.645

If Z>

1.4 > 1.645

Therefore, we do not reject null hypothesis at 5% significant level.

There is sufficient evidence that the mean impurity in concentration pills is 3% or less than 3%.

p-value

p−value=P(Z>1.4)

=1−P(Z<1.4)

=1−0.90988

=0.0901

Therefore, the p-value for the given test is 0.0901.

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Answer:

c

Step-by-step explanation:

Marl me as brainliest answer c

Answer:

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

Step 2: Multiply both sides by 20/(-1).

Hope this helped you!

Answer:

a) probability that neither is Tay-Sachs carrier is 0.9298

b) the probability that both are carriers is 0.001276

Step-by-step explanation:

Given that;

1 in 28 people of Ashkenazi jewish descent are Tay-Sachs carrier.

so P(Carrier) = 1/28 =

also P( Not a carrier) = 1 - 1/28 = 0.9643

Now After Sampling 1 man and 1 woman from the population;

a)

the probability neither is Tay-Sachs carrier

P( Neither is a Carrier) = 27/28 × 27/28 = 0.9298

Therefore probability that neither is Tay-Sachs carrier is 0.9298

b)

the probability both are carriers

P( Both are Carriers) = 1/28 × 1/28 = 0.001276

Therefore the probability that both are carriers is 0.001276

Final answer:

The probability of both a man and a woman of Ashkenazi Jewish descent not being Tay-Sachs carriers is calculated as (27/28) * (27/28). The probability of both being carriers is (1/28) * (1/28).

Explanation:

The probability of an event occurring is calculated as the number of favorable outcomes divided by the total number of outcomes. In this case, the problem is related to genotypes and their associated probabilities, aligning with the concept of probability in mathematics.

The probability of a person of Ashkenazi Jewish descent not being a Tay-Sachs carrier is 27/28 because 1 out of 28 are carriers, and thus 27 out of 28 are not. For two independent events, the probability of both occurring is obtained by multiplying their individual probabilities. Therefore, the probability of both the man and the woman not being carriers is (27/28) * (27/28).

Similarly, the probability that both are carriers would be calculated as (1/28) * (1/28).

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Answer:

A. $4397.9

Step-by-step explanation:

We are given that Kendra sold 200 shares and that the price per share was $22.1

This means that:

Total value = 200 * 22.1 = $4420

Now, we know that the broker charged 0.5% commission on the total value

This means that:

Broker's charge = 0.5% * 4420 = 0.005 * 4420 = $22.1

Therefore,

Kendra's return = Total value - broker's charge

Kendra's return = 4420 - 22.1 = $4397.9

Hope this helps :)

Answer:

A) P(soft drink, hamburger, no fries) = 0.1912

B) P(fries and hamburger) = 0.3763

Step-by-step explanation:

A) Probability that the order will include a soft drink, a hamburger and no fries is;

P(soft drink, hamburger, no fries) = P(soft drink) x P(hamburger) x P(no French fries)

P(soft drink, hamburger, no fries) = 0.88 x 0.53 x (1 - 0.49) = 0.88 × 0.53 × 0.41 ≈ 0.1912

B) we are told that;

P(fries|hamburger)=0.71

Since P(fries|hamburger) = P(fries and hamburger)/P(hamburger)

Thus;

0.71 = P(fries and hamburger)/0.53

P(fries and hamburger)= 0.71 *0.53

P(fries and hamburger) = 0.3763

Final answer:

Question a's answer is 0.4488 meaning there's a 44.88% chance a customer will order a soft drink and no fries. For question b, the answer is 0.3763 meaning there's a 37.63% chance that an order will include a hamburger and fries.

Explanation:

To calculate probabilities of independent events, you simply multiply the probability of each event happening.

For question a. the probability of ordering a soft drink is given as 0.88, and the probability of ordering fries is given as 0.49. However, we want the probability of ordering a soft drink and not ordering fries, which means we need to take the complement of the fries event (1-0.49) which is 0.51. Multiply the probability of ordering a soft drink (0.88) with the probability of not ordering fries (0.51):

0.88 x 0.51 = 0.4488

Therefore the probability of a customer ordering a soft drink and no fries is 0.4488.

For question b. we are given the conditional probability that a customer will order fries given they have already ordered a hamburger, which is 0.71. To calculate the joint probability of both events (hamburger and fries), we must multiply the conditional probability by the probability of the hamburger event:

0.71 x 0.53 = 0.3763

Therefore the probability of an order including a hamburger and fries is 0.3763.

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