The balanced chemical equation between solid chromium and solid iodine to form solid chromium(III) iodide is: 2 Cr(s) + 3 I₂(s) ⇒ 2 CrI₃(s)
Let's consider the unbalanced equation that occurs when solid chromium reacts with solid iodine to form solid chromium(III) iodide. This is a synthesis or combination reaction.
Cr(s) + I₂(s) ⇒ CrI₃(s)
We will balance it using the trial and error method.
First, we will balance I atoms by multiplying I₂ by 3 and CrI₃ by 2.
Cr(s) + 3 I₂(s) ⇒ 2 CrI₃(s)
Finally, we get the balanced equation by multiplying Cr by 2.
2 Cr(s) + 3 I₂(s) ⇒ 2 CrI₃(s)
The balanced chemical equation between solid chromium and solid iodine to form solid chromium(III) iodide is: 2 Cr(s) + 3 I₂(s) ⇒ 2 CrI₃(s)
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Answer:
2 Cr(s) + 3 I2(s) → 2 CrI3(s)
Explanation:
Reactants:
Solid Chromium
• Chromium is a transition metal with an elemental symbol → Cr
• It can exist as a stable monatomic solid → Cr(s)
Solid Iodine
• Iodine is a non-metal halide of Group 7A → I
• It exists as a diatomic solid → I2(s)
Products:
Chromium(III) iodide
• Chromium, Cr → roman numeral III → +3 charge → Cr3+
• Iodide, I → from group 7A → -1 charge → I-
• When ions combine, their charges or oxidation numbers crisscross to become subscripts
• Cr will have a subscript of 1 from I- → Cr
• I will have a subscript of 3 from Cr3+ → I3
• Subscript 1 is no longer indicated → CrI3(s)
Unbalanced Chemical Reaction: Cr(s) + I2(s) → CrI3(s)
Balancing the chemical reaction:
1. Balance I:
Cr(s) + I2(s) → CrI3(s)
• There are 2 I in the reactant and 3 I in the product side
• Balance I by adding the coefficient 3 in I2 and 2 in CrI2
• There would be a total of 6 I in the reactant and product sides
Cr(s) + 3 I2(s) → 2 CrI3(s)
2. Balance Cr:
Cr(s) + 3 I2(s) → 2 CrI3(s)
• There is 1 Cr in the reactant and 2 Cr in the product side
• Balance Cr by adding the coefficient 2 in Cr(s)
• There would be a total of 2 Cr in the reactant and product sides
2 Cr(s) + 3 I2(s) → 2 CrI3(s)
The skeletal system of a human body is the only one that can get fossilized. The remains of ancient species are preserved as fossils. Body parts must typically be hard and able to be mineralized without losing their form or degrading in order to become fossilized.
Any surviving remnants, impression, or evidence of a once-living creature from a previous geological epoch is referred to as a fossil. Examples include fossilized bones, shells, exoskeletons, animal or microbe impressions in stone, amber-preserved artifacts, hair, petrified wood, oil, coal, and DNA traces.
In river valleys, cliffs, hillsides, and man-made exposures like quarries and road cuts, sedimentary rocks of the appropriate age are exposed, and these are the places where fossils are most frequently found.
The most typical kind of fossilization takes place quickly after an animal dies when it is buried under material, such sand or silt. Sedimentary deposits shield its bones from decaying.
Thus, The remains of ancient species are preserved as fossils.
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Answer:
Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.
B The oxygen in the air forms ozone in presence of UV rays
C Dust and soot particles being suspended in the air
D Sulphur dioxide being released in the air
the answer is B not A
let me explain why see a says water vapor in the air turns to liquid water in the form of rain see that is a physical change not a chemical change it is B because it is undergoing a chemical change by the uv rays for that reason it is not D because that is just releasing sulfur dioxide in the air that is not a chemical change nor a physical change so then i leaves us with C so C is wrong because it just being suspended in the air not physical or chemical change
can i also have brainlyest i never had it before
For #1 For #2
A.grouping A.Similar element names
B.families B.Similar properties
C.periods C.Similar symbols
D.lines D.Similar masses
Vertical columns on the periodic table are called B. families.
The elements in each column, or family, have B. Similar properties.
In the periodic table, elements are organized into rows and columns based on their atomic number and electron configuration. Each vertical column represents a family or group of elements that share similar chemical and physical properties.
The elements within a family tend to have similar valence electron configurations, leading to similar chemical behaviors and reactivity patterns.
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B. [Na +3] / [PO43-]
C. [Na +] }[PO43-)
D. [Na] +3/[PO4) 3 -
The solubility product expression for Na3PO4(s) is [Na+]^3[PO4^3-], which denotes the ion concentration in the solution after the dissolution of sodium phosphate. therefore, option A is correct
The solubility product expression for Na3PO4(s) would be written as [Na+]^3[PO4^3-]. The solubility product, Ksp, is the equilibrium constant for the dissolution of a sparingly soluble substance. The solubility product expression depends on the stoichiometry of the dissolution reaction. Sodium phosphate, Na3PO4, dissociates in water into 3 sodium ions, Na+, and 1 phosphate ion, PO4^3-. Therefore, the solubility product expression is [Na+]^3[PO4^3-], where [Na+] and [PO4^3-] represent the molar concentration of these ions in the solution.
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The solubility product expression of Na3PO4 is not among the given options because Na3PO4 is soluble in water and for soluble compounds, we don't write a solubility expression.
The solubility product expression is typically written for an ionic compound that is sparingly soluble in water. The solubility product expression of Na3PO4 is not among the options you've provided because every ionic compound has its own specific solubility product expression. Na3PO4 is soluble, so we don't write a solubility expression for it. In general, for a reaction where a solid dissolves in water such as A3B (s) ↔ 3A+ (aq) + B3- (aq), the solubility product expression would be [A+]^3 [B3-].
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