Use the technique developed in this section to solve the minimization problem. Minimize C = −3x − 2y − z subject to −x + 2y − z ≤ 20 x − 2y + 2z ≤ 25 2x + 4y − 3z ≤ 30 x ≥ 0, y ≥ 0, z ≥ 0 The minimum is C = at (x, y, z) = .

Answers

Answer 1
Answer:

Answer:

C= -145, (35/4, 295/8, 45)

Step-by-step explanation:

Use Gaussian elimination to find the values of x, y and z

Eq 1: -x+2y-z=20

Eq 2: x-2y+2z=25

Eq 3: 2x+4y-3z=30

  • Multily Eq1 by 1 and add to Eq 2

Eq 1: (-x+2y-z=20 ) × 1

Eq 2:  x-2y+2z=25

Eq 3:  2x+4y-3z=30

⇒ Eq1: -x+2y-z=20

    Eq2:         z= 45

   Eq 3: 2x+4y-3z=30

  • Multiply Eq 1 by 2 and then add to Eq 3

Eq1:  (-x+2y-z=20 ) × 2

Eq2:            z= 45

Eq3:   2x+4y-3z=30

⇒ Eq1:  -x+2y-z=20

   Eq2:            z= 45

  Eq3:      8y-5z= 70

  • swap Eq 2 and Eq 3

Eq 1: -x+2y-z=20

Eq 3:     8y-5z= 70

Eq 2:       z= 45

  • Solve Eq 2 for z

Z=45

  • solve Eq Eq 3 for y.

y= 295/8

  • Using the value z=45 and y= 295/8, substitue in Eq 1 to get value of x

x= 35/4

  • Substitue values of x,y and z in C= -3x-2y-z to get minimum value of C

C= -145


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At what x-values do the graphs of the functions y = cos 2x and y =3cos^2x-sin^2x intersect over the interval -pi

Answers

To find:

The x-values at the intersection of the graphs of two functions.

Solution:

Two functions are:

y=\cos2x\text{ and }y=3\cos^2x-\sin^2x

The functions are equal at the intersection. So,

\cos2x=3\cos^2x-\sin^2x

The solutions of the above equation are the x-values of the intersection.

\begin{gathered} \cos2x=3\cos^2x-\sin^2x \n \cos^2x-\sin^2x=3\cos^2x-\sin^2x \n 2\cos^2x=0 \n \cos^2x=0 \n \cos x=0 \end{gathered}

The solution to the above equation is:

x=(\pi)/(2)+2\pi n\text{ and }x=(3\pi)/(2)+2\pi n

It is given that x lies between -pi and pi. So, the value of n = 0 for the first solution and n = 1 for the second solution. Therefore,

x=(\pi)/(2)\text{ and }x=-(\pi)/(2)

Thus, options A and B are correct.

Multiply. Write your answer in simplest form.
-√2(-2+√5)

Answers

Step-by-step explanation:

this is all I can find I hope it helps you out us not I'm sorry

suppose that you made four measurement of a speed of a rocket: 12.7 km/s, 13.4 km/s, 12.6 km, and 13.3 km/s. compute: the mean, the standard deviations, and the standard deviation of the mean

Answers

Answer:

Mean = 13 kilometer per second

Standard Deviation = 0.4082 kilometer per second

Step-by-step explanation:

We are given the following data set of rocket speed in kilometer per second in the question:

12.7, 13.4, 12.6, 13.3

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle(52)/(4) = 13

Deviations from mean = -0.3, 0.4, -0.4, 0.3

Sum of squares of differences =

0.09 + 0.16 + 0.16 + 0.09 = 0.5

S.D = \sqrt{(0.5)/(3)} = 0.4082

Mean = 13 kilometer per second

Standard Deviation = 0.4082 kilometer per second

16. The original price of a tie is $12.50. The new price of the tie is now$7.50. By what percentage was the tie marked down? *

Answers

The tie was marked down by 40%

Mrs. Smith is giving a homework pass to a student whose expression is equivalent to - i. Which expression will win the homework pass?A. i^36
B. i^37
C. i^38
D. i^39
Help pleaseee

Answers

Answer:

D. i^39

Step-by-step explanation:

If you simplify i^39, you get i^35, i^31, i^27, i^23, i^19, i^15, i^11, i^7, to i^3, which is equal to -i.

How do you do this question?

Answers

Step-by-step explanation:

K is an upper bound for│f"(x)│on the interval [0, 1], so x ≤ 1.

Sine and cosine have maximums of 1, so an upper bound of │f"(x)│is:

│f"(x)│≤ (76 · 1 + 152 · 1 · 1)

│f"(x)│≤ 228