Find the gradient of the line segment between the points (-8,6) and (-10,14)

Answers

Answer 1
Answer:

The required gradient of the line between the points (-8,6) and (-10,14) is -4.

What is the slope of the line?

The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.

Here,
The gradient of the line segment between points (-8,6) and (-10,14) is given as,

The gradient of the line = slope of the line,
m = (y₂ - y₁) /  (x₂ - x₁)

Substitute the value in the above equation,
m = 14- 6 / -10 + 8
m = 8 / -2
m = -4

Thus, the required gradient of the line between the points (-8,6) and (-10,14) is -4.

Learn more about slopes here:
brainly.com/question/3605446

#SPJ5

Answer 2
Answer:

Answer:

-4

Step-by-step explanation:

14 - 6 = 8

-10 - - 8 = - 2

8 / - 2 = - 4


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4y-11=21 what is the value of y

Answers

4y-11=21
Add 11 to 21.
4y=32
Divide both sides by 4.
y=8


My steps may be really weird, but please don't ridicule me. 

1. 11+21
2. 32 divides 4
3. 8
So, y is 8.

Holly bought CDS and spent $34.57 . what is the amount rounded to the nearest dollar

Answers

As the second part of the cost is above 0.5, this means that it is being rounded up.
Therefore, it is rounded up to $35
Hope this helps :) 
The answer is $35 becuause you have to round 4 up

Joe purchased a tray of 48 petunias to plant in his garden. The graph shows points representing the number of flowers left to plant at several different times while Joe is planting.___x + y = ___

Answers

i think 2,24 + 4
            

.........................................sorry for the dots 









. Tina walked 20 miles for a fundraiser. Liawalked m miles. Tina walked 4 times as
far as Lia. Which equation can be used to
find m, the number of miles Lia walked?

Am= 4 x 20
B20 = 4 x m
C20 = m = 4
Dm = 20 + 4

Answers

Answer:

The relation for the distance cover by Tina and Lia is 20 = 4 × m

Option B

Step-by-step explanation

Given as :

The distance cover by Tina = D_1 = 20 miles

The distance cover by Lia = D_2 = m miles

According to question

Tina walked 4 times as far as Lia

So, The distance cover by Tina = 4 × The distance cover by Lia

Or, D_1 = 4 ×  D_2

I.e 20 miles = 4 × m miles

or. 20 = 4 × m

So, relation is 20 = 4 × m

Hence, The relation for the distance cover by Tina and Lia is 20 = 4 × m

I.e option B  Answer

If c(x) = 4x – 2 and d(x) = x^2+ 5x, what is (c circle d) (x)?

Answers

Answer:

4x² + 20x - 2

Step-by-step explanation:

To evaluate (c ○ d)(x), substitute x = d(x) into c(x)

c(x² + 5x)

= 4(x² + 5x) - 2

= 4x² + 20x - 2

Which values of p and q would make the value of the following expression equal to 58i? (3 – 7i)(p + qi)i

Answers

we are given

(3-7i)(p+qi)i=58i

firstly, we will simplify left side

and then we can compare it with right side

so, we can distribute

(3p+3qi-7pi-7qi^2)i=58i

(3p+3qi-7pi+7q)i=58i

we have i on both sides

so,i will get cancelled

(3p+3qi-7pi+7q)=58

(3p+7q+(3q-7p)i)=58

we can also write as

(3p+7q)+(3q-7p)i=58+0*i

now, we can compare

and we get

3p+7q=58

3q-7p=0

now, we can solve for p and q

we get

q=7,\:p=3.............Answer


Answer:

For short the answer is A.      p = 3 , q = 7