A 4.0L weather balloon is launched from sea level where the temperature is 25°C. It rises to an altitude where the pressure is 0.05atm and the temperature is -75°C. If the balloon has the capacity to expand to a 50 liter volume before bursting, will the balloon survive?

Answers

Answer 1
Answer:

Answer: The balloon will not survive.

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

(P_1V_1)/(T_1)=(P_2V_2)/(T_2)

where,

P_1 = initial pressure of gas =  1 atm

P_2 = final pressure of gas = 0.05 atm

V_1 = initial volume of gas = 4.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 25^oC=273+25=298K

T_2 = final temperature of gas = -75^oC=273-75=198K

Now put all the given values in the above equation, we get:

(1* 4.0)/(298)=(0.05* V_2)/(198)

V_2=53.2L

As the balloon has the capacity to expand to a 50 liter volume before bursting, it can not survive as it occupies volume higher than 50 L


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Answers

Answer:

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Answer:

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