A 2210 kg 2210 kg space station orbits Earth at an altitude of 5.39 × 10 5 m. 5.39×105 m. Find the magnitude of the force with which the space station attracts Earth. The mass and mean radius of Earth are 5.98 × 10 24 kg 5.98×1024 kg and 6.37 × 10 6 m, 6.37×106 m, respectively.

Answers

Answer 1
Answer:

Answer:

18466.68 N

Explanation:

mass of satellite, m = 2210 kg

mass of earth, M = 5.98 x 10^24 kg

distance between surface of earth and the satellite, h = 5.39 x 10^5 m

radius of earth, R = 6.37 x 10^6 m

The force between the earth and the satellite is given by

F = (GMm)/(\left (R+h  \right )^(2))

F = (6.67* 10^(-11)* 5.98* 10^(24)* 2210)/(\left (6.37+0.539 \right )^(2)* 10^(12))

F = 18466.68 N


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