CAN SOMEONE PLEASE HELP I AM ALSO BEGGING! Probability theory predicts that there is a 76% chance of a water polo team winning any particular match. If the water polo team playing two matches is simulated 10,000 times, in about how many of the simulations would you expect them to win exactly one match?
Answers
Answer 1
Answer:
In each of the two match simulations, the order in which one match is won and one match is lost does not matter. The probability of winning any particular match is 0.76 and the probability of losing any particular match is 1.00 - 0.76 = 0.24.
In each simulation the probability of winning exactly one match is:
%3D2C1%5Ctimes0.76%5Ctimes0.24%3D0.3648)
Therefore in 10,000 simulations the expected number of times that exactly one match is won = 10,000 * 0.3648 = 3648 times.
In each simulation the probability of winning exactly one match is:
Therefore in 10,000 simulations the expected number of times that exactly one match is won = 10,000 * 0.3648 = 3648 times.
Answer 2
Answer:
Answer:
3648
Step-by-step explanation:
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Step-by-step explanation:
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