3.30 Measurements of scientific systems are always subject to variation, some more than others. There are many structures for measurement error, and statisticians spend a great deal of time modeling these errors. Suppose the measurement error X of a certain physical quantity is decided by the density function f(x) = k(3 − x2), −1 ≤ x ≤ 1, 0, elsewhere. (a) Determine k that renders f(x) a valid density function. (b) Find the probability that a random error in measurement is less than 1/2. (c) For this particular measurement, it is undesirable if the magnitude of the error (i.e., |x|) exceeds 0.8. What is the probability that this occurs?

Answers

Answer 1
Answer:

Answer:

a) k should be equal to 3/16 in order for f to be a density function.

b) The probability that the measurement of a random error is less than 1/2 is 0.7734

c) The probability that the magnitude of a random error is more than 0.8 is 0.164

Step-by-step explanation:

a) In order to find k we need to integrate f between -1 and 1 and equalize the result to 1, so that f is a density function.

1 = k \int\limits^1_(-1) {(3-x^2)} \, dx = k  *  (3x-(x^3)/(3))|_(x=-1)^(x = 1) = k*[(3-1/3) - (-3 + 1/3)] = 16k/3

16k/3 = 1

k = 3/16

b) For this probability we have to integrate f between -1 and 0.5 (since f takes the value 0 for lower values than -1)

P(X < 1/2) = \int\limits^(0.5)_(-1) {(3)/(16)(3-x^2)} \, dx = (3)/(16) [(3x-(x^3)/(3)) |_(x=-1)^(x=0.5)] =(3)/(16) *(1.458333 - (-3+1/3)) = 0.7734

c) For |x| to be greater than 0.8, either x>0.8 or x < -0.8. We should integrate f between 0.8 and 1, because we want values greater than 0.8, and f is 0 after 1; and between -1 and 0.8.

P(|X| > 0.8) = \int\limits^(-0.8)_(-1) {(3)/(16)*(3-x^2)} \, dx + \int\limits^(1)_(0.8) {(3)/(16)*(3-x^2)} \, dx =\n (3)/(16) (3x-(x^3)/(3))|_(x=-1)^(x=-0.8) + (3)/(16) (3x-(x^3)/(3))|_(x=0.8)^(x=1) = 0.082 + 0.082 = 0.164

Answer 2
Answer:

(a) The value of k that makes f(x) a valid density function is k = 1/6.

(b) The probability that a random error in measurement is less than 1/2 is 3/4.

(c) The probability that the magnitude of the error exceeds 0.8 is 1/4.

(a) To make the given function f(x) a valid probability density function, it must satisfy the following conditions:

The function must be non-negative for all x: f(x) ≥ 0.

The total area under the probability density function must equal 1: ∫f(x)dx from -1 to 1 = 1.

Given f(x) = k(3 - x^2), -1 ≤ x ≤ 1, and f(x) = 0 elsewhere, let's find the value of k that satisfies these conditions.

Non-negativity: The function is non-negative for -1 ≤ x ≤ 1, so we have k(3 - x^2) ≥ 0 for -1 ≤ x ≤ 1. This means that k can be any positive constant.

Total area under the probability density function: To find the value of k, integrate f(x) over the interval [-1, 1] and set it equal to 1:

∫[from -1 to 1] k(3 - x^2)dx = 1

∫[-1, 1] (3k - kx^2)dx = 1

Now, integrate the function:

[3kx - (kx^3/3)] from -1 to 1 = 1

[(3k(1) - (k(1^3)/3)) - (3k(-1) - (k(-1^3)/3))] = 1

Simplify:

[3k - k/3 + 3k + k/3] = 1

6k = 1

k = 1/6

So, the value of k that makes f(x) a valid density function is k = 1/6.

(b) To find the probability that a random error in measurement is less than 1/2, you need to calculate the integral of f(x) from -1/2 to 1/2:

P(-1/2 ≤ X ≤ 1/2) = ∫[from -1/2 to 1/2] f(x)dx

P(-1/2 ≤ X ≤ 1/2) = ∫[-1/2, 1/2] (1/6)(3 - x^2)dx

Now, integrate the function:

(1/6) [3x - (x^3/3)]from -1/2 to 1/2

[(1/6)(3(1/2) - ((1/2)^3/3)) - (1/6)(3(-1/2) - ((-1/2)^3/3))]

Simplify:

(1/6)[(3/2 - 1/24) - (-3/2 + 1/24)]

(1/6)[(9/8) + (9/8)]

(1/6)(18/8)

(3/4)

So, the probability that a randomerror in measurement is less than 1/2 is 3/4.

(c) To find the probability that the magnitude of theerror (|x|) exceeds 0.8, you need to calculate the probability that |X| > 0.8. This is the complement of the probability that |X| ≤ 0.8, which you can calculate as:

P(|X| > 0.8) = 1 - P(|X| ≤ 0.8)

P(|X| > 0.8) = 1 - P(-0.8 ≤ X ≤ 0.8)

We already found P(-0.8 ≤ X ≤ 0.8) in part (b) to be 3/4, so:

P(|X| > 0.8) = 1 - 3/4

P(|X| > 0.8) = 1/4

So, the probability that the magnitude of the error exceeds 0.8 is 1/4.

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Answers

  3x + 5y =  -1
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The answer is C.

A bicycle is on sale at $12 more than half of the regular price. If the sale price is $75, find the regular price.

Answers

The regular price of the bicycle will be $126.

What is an expression?

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that a bicycle is on sale at $12 more than half of the regular price and the selling price is $75.

The regular price of the bicycle will be calculated as below:-

( P / 2 ) + 12 = 75

P  + 24 = 150

P = 150 - 24

P = 126

Therefore, the regular price of the bicycle will be $126.

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so 12 more than half the regular price.
let's let p be the original price.

(1)/(2) p + 12 = 75
right?
Now you just have to solve from there.

Can you guys help me. l will give you the brainliest and if you give me the correct answers. please show working.

Answers

Answer:

Step-by-step explanation:

Angles formed when we turn clockwise in the given directions,

a) N to E → 90°

b). W to NE → (90° + 45°) = 135°

c). SE to NW → 180°

d). NE to N → 360° - 45° = 315°

e). W to NE → 90° + 45° = 135°

f). S to SW → 45°

g). S to SE → 360° - 45° = 315°

h). SE to SW → 180°

i). E to SW → 90° + 45° = 135°

Raise the following number to the indicated power.
(-4)2 =

Answers

If it’s -4 to the power of 2
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Answer:

16

Step-by-step explanation:

Exponential growth or exponential decay last question please help ?

Answers

This is exponential growth because the peak starts at the negative side and it ends up at the positive side. Therefore, it is exponential growth.

Answer:

exponential decay

Step-by-step explanation:

It's going down towards the positive area.

Which inequality will have a dashed boundary line with a shaded area above its graph? 7x − y ≤ 3 x − y ≤ 4 2x − 9y > 2 4x + 7y > 3

Answers

above the graph

look at them

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dashed boundary line means it does't include htat means taat the symbol is < or >

cross out first 2

one way is to graph the lines as equations and shade accordingly

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y>-7/4x+3/9
shade on top


aswer is 4x+7y>3

Answer:

its D

Step-by-step explanation: