Two charges q1 and q2 are separated by a distance, d, and exert a force, F, on each other.Which best represents the new force F′ if q1 is tripled?

Answers

Answer 1
Answer:

If the charge q₁ is tripled  then the force between the charged becomes 3 times the original charge.

Explanation:

Given:

Distance between the two charges = r

The force between two charges is given by:

F_1 = k(q_1q_2)/(r^2)

If q₁ is tripled, then the force F becomes:

F_2 = k((3q_1)Xq_2)/(r^2)

(F_2)/(F_1) = (3q_1q_2)/(r^2) X (r^2)/(q_1q_2)\n\nF_2 = 3F_1

Therefore, if the charge q₁ is tripled  then the force between the charged becomes 3 times the original charge.

Answer 2
Answer:

Answer:

F′ = 3 F

Explanation:


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