Jane thought of a number then added -5 and subtracted -8 to get 13. What number did Jane start with

Answers

Answer 1

Answer: Rephrased: Jane thought of a number, subtracted 5, and added 8 to get 13. -5+8=3. 13-3=10. Jane’s number is 10.

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My Prime factors are 2,3, and 5, and I am a number between 58 and 68. What number am I?

Answers

The number should be 65.

Given that,

The prime factors are 2,3, and 5.
And, the number between 58, and 68.
We have to find out that number.

Based on the above information,

The number should be 60 and 65.
But the 60 should be divisible by 2,3 but the 65 is not divisible by 2 and 3.

Therefore we can conclude that the number should be 65.

Learn more: brainly.com/question/17429689

Well, because the number has to be a multiple of 5, it must be either 60 or 65. Then, you see that only 60 fits the description because it is divisible by both 2 and 3 while 65 is divisible evenly by neither

Which of the following equations results in no solutions?A 3(u + 5) = 2u + 15
B 3(u + 5) = 2u + 15 + u
C 3(u + 5) = 2u - 4 + u
D 3(u + 5) = 2u - 4
need help please

Answers

It will be B because Problem A,C,D is wrong not Problem B

What is the value of (16^3/2)^1/2

Answers

Lets see,

$16^{{3/2}^(1/2)}=16^(3/2 \cdot 1/2)=16^(3/4)=2^(3)=8$ .

Hope this helps.

What is 0.03703703703 as a fraction

Answers

$n=0.\dot { 0 } 3\dot { 7 } \n \n 1000n=37.\dot { 0 } 3\dot { 7 } \n \n 1000n-n=37$

$\n \n 999n=37\n \n n=\frac { 37 }{ 999 } \n \n n=\frac { 37 }{ 37 } \cdot \frac { 1 }{ 27 } \n \n \therefore \quad n=\frac { 1 }{ 27 }$

$x=0.\overline{037}\n1000x=37.\overline{037}\n1000x-x=37.\overline{037}-0.\overline{037}\n999x=37\nx=(37)/(999)=(1)/(27)$