A right triangle has the leg lengths of 3X and 40 and a hypotenuse of length 5X. How long are the sides?

Answers

Answer 1

Answer:

Answer:

Hypotenuse = 10 units

Step-by-step explanation:

According to the Pythagoras theorem:

${hyp}^(2) = {(one \: leg) }^(2) + {(other \: leg)}^(2) \n \therefore \: {(5x)}^(2) = {(3x)}^(2) + {40}^(2) \n \therefore \: {25x}^(2) = {9x}^(2) + 1600 \n \therefore \: {25x}^(2) - {9x}^(2)= 1600 \n \therefore \: {16x}^(2)= 1600 \n \therefore \: {x}^(2)= (1600)/(16) \n \therefore \: {x}^(2)= 100 \n \therefore \: {x}= 10 \n$

Hence, length of hypotenuse = 10 units.

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Is it possible to draw a triangle with sides that are 4 inches, 5 inches, and 8 inches long? Justify your answer

Answers

Yes, because 4+5>8....

yea because 4+5 is 9 and 8 is less than 9

What times what will give me 30

Answers

What times what will give me 30
the answer is 6x5

5*6=30 because I did it in my head and I know how to multiply.

What is the value of z?

Answers

Solve:-

This triangle's angles sum should equal to 180°. Lets find z:-

180 - 62 = 118
118 - 95 = 23

Angle z = 23°

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A. The equation is a nonlinear function.
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