Two polarizers are arranged as shown. How much light will reach point X?0%
more than 50% but less than 100%
50%
less than 50% but more than 0%
100%
Answers
Answer:
50% if light is unpolarized
100% if light is horizontally polarized
0% if light is vertically polarized
Explanation:
A polarizer has an axis that "blocks" the component of light in the direction perpendicular to the direction of the polarizer axis.
When unpolarized light passes through a polarizer, the intensity of light is reduced to , where
is the initial intensity of the light: this is because only the component of the light parallel to the axis of the polarizer will pass through, and this component makes 1/2 of the incident light intensity. In this case, since the axis of the polarizer is horizontal, only the horizontal component of the light will pass through, while the vertical component will be blocked. So in this case the final intensity will be 50% of the initial one.
On the other hand, if the incoming light is already horizontally polarized (same orientation as the polarizers), there is no vertical component to block, so all the light passes through the polarizer; therefore, the final intensity will be 100% of the original intensity.
Finally, if the incoming light is vertically polarized, no light will pass through it, because the polarizer's axis is horizontal, so it will block all the vertically polarized light: so the final intensity will be 0% of the original intensity.
All of this is after passing the 1st polarizer; so, after passing the 1st polarizer, the light is now horizontally polarized. Then, the intensity of the light passing through the 2nd polarizer is given by Malus' Law:
where is the angle between the axes of the two polarizers. Since here the two polarizers axes are parallel to each other,
, so
, and so the intensity after the 2nd polarizer is exactly the same as the intensity after the 1st polarizer.
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a negatively charged electron cloud surrounding a positively charged nucleus
a negatively charged electron cloud surrounding a negatively charged nucleus
Answers
Nucleus consists of electrically neutral neutrons and positively charged protons, so it is positively charged. Electrons, on the other hand are negatively charged. Electromagnetic force bounds atoms to the nucleus.
Final answer:
An atom is described as a negatively charged electron cloud surrounding a positively charged nucleus.
Explanation:
An atom is the basic unit of matter, consisting of a nucleus at its center, composed of protons and neutrons, and electrons orbiting the nucleus. It is the fundamental building block of elements, and the arrangement of electrons determines an atom's chemical properties.
An atom is described as a negatively charged electron cloud surrounding a positively charged nucleus. The nucleus of an atom contains positively charged protons and electrically neutral neutrons, while the negatively charged electrons exist in the electron cloud surrounding the nucleus. This model of the atom is known as the Bohr model, which accurately represents the distribution of electrons in an atom.
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#SPJ
O wrist monitor
Answers
Answers
Answer:
Explanation:
At t = 1 velocity = 0
At t = 3 velocity = 3
slope of the line = 3-0 / 3-1 = 3/2
At t = 2
velocity = 3/2 x ( 2 - 1 )
= 1.5 m /s
velocity at t = 2 is 1.5 m /s
Position at t = 2 :
displacement at t = 2
area of graph upto t = 2
= 1 / 2 x 1 x 1.5 = .75
position at t = 2 :
= initial position + displacement
= 10 + .75 = 10.75 m
position at 6 s :
displacement at t = 6
area of curve upto t = 6
= 1 / 2 x 2 x 3 + 3 x 3 + 1/2 x 3 x ( 4.5 - 3 )
= 3 + 9 + 2.25
= 14.25 m
position at t = 6
= initial position + displacement
= 10 + 14.25 = 24.25 m
position at 9 s :
displacement at t = 9
area of curve upto t = 9
= 1 / 2 x 2 x 3 + 4 x 3 + 1/2 x 4 x ( 5 - 3 )- 1/2 x 2 x 1.5
= 3 + 12 + 4 - 1.5
= 17.5 m
position at t = 9
= initial position + displacement
= 10 + 17.5 = 27.5 m
Answers
Answer:
190 is the average velocity.
Explanation:
Just add them together
Answers
Here are the following choices:
a. Tension and gravity
b. tension, gravity and centripetal force
c. Tension
d. Tension gravity centripetal force and frictional force
Answers
Answer:
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