If it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution, what is the concentration of the NaOH solution? (Round answer to 4 decimal places) *
Answers
Answer:
Concentration of NaOH= 0.0036 M
Explanation:
Given data:
Volume of HCl = 25 mL
Concentration of HCl = 0.05 M
Volume of NaOH = 345 mL
Concentration of NaOH = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Concentration of HCl
V₁ = Volume of HCl
C₂ = Concentration of NaOH
V₂ = Volume of NaOH
Now we will put the values in formula.
C₁V₁ = C₂V₂
0.05 M × 25 mL = C₂ × 345 mL
1.25 M.mL = C₂ × 345 mL
C₂ = 1.25 M.mL/345 mL
C₂ = 0.0036 M
Final answer:
To find the concentration of the NaOH solution, we can use the concept of titration. By using the equation Moles = Concentration * Volume, we can calculate the moles of HCl used and then use the ratio of moles between HCl and NaOH to find the concentration of the NaOH solution.
Explanation:
To find the concentration of the NaOH solution, we need to use the concept of titration. From the given information, it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution. We can use the equation Moles = Concentration * Volume to find the amount in moles of HCl used. Then, we can use this information to calculate the concentration of the NaOH solution.
First, let's calculate the moles of HCl used:
Moles of HCl = (0.05 M) x (0.025 L) = 0.00125 mol
Next, we can use the ratio of moles between HCl and NaOH, which is 1:1, to find the moles of NaOH in the solution:
Moles of NaOH = 0.00125 mol
Finally, we can calculate the concentration using the formula:
The concentration of NaOH = (0.00125 mol) / (0.345 L) = 0.00362 M
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