MATHEMATICS MIDDLE SCHOOL

louis and valentina have 60 toys to build louis builds 1/2of the toys while valentina builds 2/5 how many toys are left

Answers

Answer 1
Answer:

Answer:

6

Step-by-step explanation:

Louis build 1/2 of the toy and the total of the toy is 60

Which means

1/2×60=30

Valentina build 2/5 toy

2/5×60

120/5

24

So to determine the amount left

It will be

Total-(Louis+Valentina)

60-(30+24)

60-(54)

60-54

6

So the amount left is 6
Answer 2
Answer:

Answer:

6

Step-by-step explanation:

1/2 = 0.5

2/5 = 0.4

60 × 0.5 = 30

60 × 0.4 = 24

30 + 24 = 54

60 - 54 = 6

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Number three, what is the answer?

Answers

Dario went -60 feet below

What is 428.6401 rounded to the nearest whole number ?

Answers

it would be 429 because 5 or more go next door for or less home is best. and 8 is greater then 5
Since you're rounding to the nearest whole number, you use the tenths place to determine how to round it. 6 ≥ 5 so the ones place is rounded up, making 429 your answer.

Claudia did homework for 2 hours. She did science homework for 47 minutes, math homework for 37 minutes, and Spanish homework for the rest of the time. What percentage of Claudia’s homework time did she spend on Spanish homework?

Answers

Is 47 hope it help you

You should do 47

47 - 37 = 10

She spent 10 minutes on her Spanish homework

I need help is it A B C or D

Answers

I believe the answer is B.
To be parallel the lines must have the same gradient (which in this question is 2). The answer must either be B or D.

To find the correct one you can substitute in the value of X and see which gives the value of Y we are looking for.

Equation B:
y=2x+5
=2×3+5
=6+5
=11

Equation D:
y=2x-19
=2×3-19
=6-19
=-13

We are looking for a value of 11 so B is correct.
Yes i agree B. y=2x+5, is the correct answer

Write 35.2 in a word form

Answers

35.2 in word form is: Thirty Five and 2 Tenths.
HOPE I HELPED!!!
:)
Thirty five and two tenths

Find the minimum value of 1 + 3(3 −x)²

Answers

for\ every\ x\in R\ is\ (3-x)^2 \geq 0\n\n (3-x)^2 \geq 0\ \ \ \Rightarrow\ \ 3 (3-x)^2 \geq 0\ \ \ 1+ (3-x)^2 \geq 1\n \nAns.\ The\ minimum\ value\ is\ 1
1 + 3(3 −x)² >= 1, because 3 > 0 and (3 −x)² >=0 =>
 the minimum value of 1 + 3(3 −x)² is 1.
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