MATHEMATICS COLLEGE

Subtract breaking apart 143-79

Answers

Answer 1

Answer:

Step-by-step explanation:

A two-digit number, such as 79, contains a tens place and a ones place.

That is because 79 is also equal to 70 + 9.

The tens place is thus the 7, since since 7 × 10 = 70

and the ones place is the 9.

So lets Subtract breaking apart 143 - 79.

Break 79 down into its parts:

70 + 9.

Subtract 70 from the original number:

143 - 70 = 73

Subtract 9 from the answer:

73 - 9 = 64

Therefore, 64 is the final answer.

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According to a recent report, 60% of U.S. college graduates cannot find a full time job in their chosen profession. Assume 57% of the college graduates who cannot find a job are female and that 18% of the college graduates who can find a job are female. Given a male college graduate, find the probability he can find a full time job in his chosen profession? (See exercise 58 on page 220 of your textbook for a similar problem.)

Answers

Answer:

There is a 55.97% that a male can find a full time job in his chosen profession.

Step-by-step explanation:

We have these following probabilities:

A 60% probability that a college graduates cannot find a full time job in their chosen profession.

A 40% probability that a college graduates can find a full time job in their chosen profession.

57% of the college graduates who cannot find a job are female

43% of the college graduates who cannot find a job are male

18% of the college graduates who can find a job are female

82% of the college who can find a job are male.

Given a male college graduate, find the probability he can find a full time job in his chosen profession?

The total males are 43% of 60%(Those who cannot find a job) and 82% of 40%(Those who can find a job). So the percentage of males is $P(M) = 0.43*0.60 + 0.82*0.40 = 0.586$

Those who are males and find a job in their chosen profession are 82% of 40%. So $P(M \cap J) = 0.82*0.40 = 0.328$

$P = (P(M \cap J))/(P(M)) = (0.328)/(0.586) = 0.5597$

There is a 55.97% that a male can find a full time job in his chosen profession.

Write the ordered pair that represents y. Then find the magnitude of y.14-2,5), 2(1, 3)

a. (3. - 2); „13 units

C. (3. - 2); 2-5 units

b. (1,5): V13 units

d. (1,5); 2-7 units

Answers

Answer:

(3,-2), $√(13) }$ units

Step-by-step explanation:

the correct question is:

Write the ordered pair that represents yz. Then find the magnitude of yz . y(-2,5),z(1,3)

SOLUTION:

points given are y(-2,5) and z(1,3)

$^( \to) _(YZ) = \binom{1}{3} - \binom{ - 2}{5} = \binom{3}{ - 2}$

so, the ordered pair is (3,-2)

next is to find the magnitude:

$|^( \to) _(YZ)| = \sqrt{ {3}^(2) + ( - 2)^(2) }$

$|^( \to) _(YZ)| = √( 9 +4)$

$\n|^( \to) _(YZ)| = √(13) }$ units

What is the solution to the system of equations?3x+10y=-47
5x - 7y=40
O (1.-5)
O (1,5)
0 (-1,-5)
0 (-1,5)

Answers

Answer:

x=1 ,y=-5

Step-by-step explanation:

3x + 10y = 47

5x - 7y = 40

____________

21x + 70y = 329. equ 1

50x - 70y = 400. equ 2

subtract equ 1 from 2

=71x = 71

divide both sides by the 71

71/71 = 71/71

x = 1

_________

to find y

substitute x into either equ 1 or equ 2

am using equ 2

5x - 7y = 40

5(1) - 7y = 40

5 - 7y = 40

7y = 5 - 40

7y = -35

divide both sides by the coffecient of y

7y/7 = -35/7

y = - 5

observe as seguintes situações e sua representação em linguagem matematica dois numeros x e y são tais 2x y=6 x-y=3

Answers

Answer:

The value of x any y are "-5.29 and 0.79" and "3.79 and -2.29"

Step-by-step explanation:

Given values:

$2xy =6.....(a)\n\nx-y= 3.....(b)\n\n$

After solve equation (a) we get

$\ equation: \n\n2xy= 6\n\nxy =(6)/(2) \n\nxy = 3.....(x)\n\n$

After solve equation (b) we get

$\ equation: \n\nx-y =3\n\nx= 3+y....(x1)\n$

put the value of x in to equation (x)

$(3+y)y = 3\n$

$y^2+3y-3=0\n\n\ compare \ the \ value \ with \ ay^2+by+c=0\na= 1\nb=3\nc=-3\n\ Formula: \ny= (-b\pm√(b^2-4ac))/(2a)\ny= (-3\pm √(9+12))/(2)\ny= (-3\pm √(21))/(2)\n$

The value of y is = -5.29 and 0.79, put the value of y in x1 equation so, we get: 3.79 and -2.29

What pair of numbers shows a common factor and a common multiple of 15 and 18?

Answers

Answer:

3 is the GCF

Step-by-step explanation:

that is your answer

Answer:

Common factors of 15 and 18

Factors for 15: 1, 3, 5, and 15. Factors for 18: 1, 2, 3, 6, 9, and 18.

Step-by-step explanation:

What is the volume of a cone with the given dimensions. radius=4 cm; height= 10 cm

Answers

167.552 the volume of a cone is piR^2h/3

Answer:

$167.47 \: {cm}^(3)$

Step-by-step explanation:

$V_(cone) = (1)/( 3) \pi {r}^(2)h \n \n = (1)/( 3) \pi * {4}^(2) * 10 \n \n = (1)/( 3) * 3.14 * 16 * 10 \n \n = (1)/( 3) * \: 502.4 \n \n = 167.466667 \n \n = 167.47 \: {cm}^(3)$

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