A closed system initially containing 1×10^-3M H2 and 2×10^-3 at 448°C is allowed to reach equilibrium. Analysis of the equilibrium mixture show s that the concentration of HI is 1.87×10^ -3. Calculate Kc at 448°C for the reaction.
Answers
Answer:
1.74845
Explanation:
We have the following reaction:
I2 + H2 => 2 HI
Now, the constant Kc, has the following formula:
Kc = [C] ^ c * [D] ^ d / [A] ^ a * [B] ^ b
In this case I2 is A, H2 is B and C is HI
We know that the values are:
H2 = 1 × 10 ^ -3 at 448 ° C
I2 = 2 × 10 ^ -3 at 448 ° C
HI = 1.87 × 10 ^ -3 at 448 ° C
Replacing:
Kc = [1.87 × 10 ^ -3] ^ 2 / {[2 × 10 ^ -3] ^ 1 * [1 × 10 ^ -3] ^ 1}
Kc = 1.87 ^ 2/2 * 1
Kc = 1.74845
Which means that at 448 ° C, Kc is equal to 1.74845
Answer:
Explanation:
[H2] = 10^-3
[I2] = 2*10^-3
[HI] = 0
in equilbiirum
[H2] = 10^-3 - x
[I2] = 2*10^-3 -x
[HI] = 0 + 2x
and we know
[HI] = 0 + 2x = 1.87*10^-3
x = ( 1.87*10^-3)/2 = 0.000935
then
[H2] = 10^-3 - 0.000935 = 0.000065
[I2] = 2*10^-3 -0.000935 = 0.001065
H₂ + I ⇄ 2 HI
Initially 1 × 10⁻³ 2 × 10⁻³
Change -9.35 × 10⁻⁴ -9.35 × 10⁻⁴ +1.87 × 10⁻³
At equil 6.5 × 10⁻⁵ 1.06 5 × 10⁻³ 1.87 × 10⁻³
HI increase by 1.87 × 10⁻³M
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Answers
Final answer:
The mass of a proton is approximately equal to 1 atomic mass unit (AMU), which is much lighter than the weight of a mole of carbon atoms or 12 moles of carbon atoms.
Explanation:
The mass of a proton is approximately equal to 1 atomic mass unit (AMU). This measurement is a standardized unit of mass that physicists and chemists use to express the atomic and molecular weights of elements.
The proton, along with the neutron, makes up the nucleus of an atom, and both have approximately the same mass, which is about 1 AMU. This is substantially lighter than the weight of one mole of carbon atoms (approximately 12 grams), and even more so compared to the mass of 12 moles of carbon atoms.
Learn more about Proton Mass here:
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You can use a website called sciencebuddies to find a project
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What is the equilibrium concentration of N2O4 if the equilibrium concentration of NO2 is 0.785 M?
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hope this helps!
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