Mrs. Smith's reading class can read an average of 175 words per minute with a standard deviation of 20 words per minute. The top 3% of the class is to receive a special award. What is the minimum number of words per minute astudent would need to read in order to get the award? Assume the data is normally distribut

Answers

Answer 1

Answer:

213 is the minimum number of words per minute a student would need to read in order to get the award

What is Normal Distribution?

Normal distribution, also known as the Gaussian distribution, is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean.

Given that, Mrs. smith reading class can read a mean of 175 words per minute with a standard deviation of 20 words per minute. The top 3% of the class is to receive a special award. we need to find the minimum number of words per minute a student would have to read in order to get the award.

The z-value separating the top 3% of a normal population from

the bottom 97%.

That value is z = 1.8808

The associated raw score value using x = zs + u

x = 1.8808*20 + 175

x = 212.62

213 is the minimum number of words per minute.

Hence 213 is the minimum number of words per minute a student would need to read in order to get the award.

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Answer 2

Answer:

Answer:

just getting ponts really sry

Step-by-step explanation:

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What represents the equal number of parts that equal a whole in a fraction.

Make h the subject of formula t=gh over 10

Answers

$t = (gh)/(10) 10t = ghh = (10t)/(g)$
I pressume this is what your question meant in the first line

V=u+at u=1 a=-3 t=1/2 work out the value and of v

Answers

Answer:

v = - $(1)/(2)$

Step-by-step explanation:

Given

v = u + at ← substitute the given values for u, a, t

= 1 + ( - 3 × $(1)/(2)$ )

= 1 + (- $(3)/(2)$ )

= 1 - $(3)/(2)$

= $(2)/(2)$ - $(3)/(2)$

= - $(1)/(2)$

Points R, S, and T are plotted on a number line. The coordinate of point R is –6. Points S and T are the same distance from point R.What could be the coordinates of S and T?

A.
S = 0, T = 6

B.
S = –4, T = –2

C.
S = –9, T = –12

D.
S = –10, T = –2

Answers

D. S=-10, T=-2 is the answer.

While we check all the given options, we will see that no option other then option D gives us the equal value of difference between R and S, and R and T; which doesn't makes the given value of S and T in option(s) A, B and C equidistant from R as given in the question. Thus, it gives us option D as the answer.

Mathematically-

Considering the option D only,

R - S = -6 - (-10) = -6 + 10 = 4
and, T - R = -2 - (-6) = -2 + 6 = 4
thus, R - S = T - R

I am confused on numbers 25 and 29, the instructions are at the top.

Answers

#25 is fairly simple. Plug in -4 and 3 into the equation, and the extraneous root will be the one that does not work.
$√(12-(-4)) = √(16) = \frac{+}{}4$
Extraneous root in this case is positive four since +4≠-4
$√(12-3) = √(9) = \frac{+}{}3$
In this case it's negative 3, since -3≠3

#29 can be turned into a quadratic equation.
$x= √(2x+3)$
Square both sides to get
$x^(2)=2x+3$
Then bring the 2x+3 to the other side, setting the quadratic equal to zero.
$x^(2)-2x-3=0$
Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1. Plug both back into the original equation. Whichever does not work is the extraneous root, and the answer is the one that does.
$x= √(2x+3)$
$3= √(2(3)+3)$
$3= √(9)$
Extraneous root would be negative 3.

$-1= √(2(-1)+3)$
$-1= √(1)$
Extraneous root would be positive 1.

Your answers are positive 3 and negative 1.
Extraneous roots are negative 3 and positive 1.

Sidney flew in an airplane five times during her vacation.The flights averaged 2 hours 28 minutes long The lengths of her first four flights were 2 hours 10 minutes,3 hours 20 minutes,1 hour 15 minutes,and 2 hours 40 minutes.What was the length of her last flight?

Answers

(everything broken down into minutes to solve)
130+200+75+160+x/5=148
*5
565+x=740
-565
x=175
x=2 hours 55 minutes

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B. y = 11/12
C. y = 144
D. y = 1/11
C

Answers

The clue to solve equations is that you can perform operations on both sides aiming to let the variable alone. For example, you can add or subtract a term as long as you do it to both sides of the equality. In this case, the variable y has 12 as coefficient, then to eliminate this coefficient you divide both sides by 12, and so you get:(12y)/12 = 132/12 => y = 11 (because 12/12 = 1 and 132/12 = 11. Then, the answer is the option A, y = 11

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