Answers
Answer:
Explanation:
Given that,
Height at which the metal sheet is submerge
H= 8ft
Fluid Force at the top side with area sheet of 3ft², A = 3ft²
Weight density of water
w = ρg = 62.4 lb/ft³
The fluid pressure can be calculated using
P = ρgh
But we are already give the weight density ρg
Then,
P = w•h
P = 62.4 × 8
P = 499.2 lb/ft²
The force from top side?
We can calculate the force using the formula for pressure
Pressure = Force /area
P = F/A
F = P×A
F = 499.2 × 3
F = 1497.6 lbs
Related Questions
Please someone help, I’m very confused and it’s due soon, thanks
When you walk at an average speed (constant speed, no acceleration) of 24 m/s in 94.1 secyou will cover a distance of__?
Suppose there are 10,000 civilizations in the Milky Way Galaxy. If the civilizations were randomly distributed throughout the disk of the galaxy, about how far (on average) would it be to the nearest civilization?
Which two types of energy does a book have as it falls to the floor
Answers
Answer:
r₁/r₂ = 1/2 = 0.5
Explanation:
The resistance of a wire is given by the following formula:
R = ρL/A
where,
R = Resistance of wire
ρ = resistivity of the material of wire
L = Length of wire
A = Cross-sectional area of wire = πr²
r = radius of wire
Therefore,
R = ρL/πr²
FOR WIRE A:
R₁ = ρ₁L₁/πr₁² -------- equation 1
FOR WIRE B:
R₂ = ρ₂L₂/πr₂² -------- equation 2
It is given that resistance of wire A is four times greater than the resistance of wire B.
R₁ = 4 R₂
using values from equation 1 and equation 2:
ρ₁L₁/πr₁² = 4ρ₂L₂/πr₂²
since, the material and length of both wires are same.
ρ₁ = ρ₂ = ρ
L₁ = L₂ = L
Therefore,
ρL/πr₁² = 4ρL/πr₂²
1/r₁² = 4/r₂²
r₁²/r₂² = 1/4
taking square root on both sides:
r₁/r₂ = 1/2 = 0.5
Final answer:
The ratio of the radius of wire A to the radius of wire B is 1/2.
Explanation:
The resistance of a wire is given by the formula R = ρl/A, where R is resistance, ρ is resistivity, l is length, and A is the cross-sectional area of the wire. When the wire has a circular cross-section, the area can be calculated by the formula A = πr². The resistance of the wire then becomes: R = ρl/(πr²). If the resistance of wire A is four times that of wire B, we can set up the equation 4RB = RA. Substituting the expression for resistance, we get 4(ρl/(πrB²)) = ρl/(πrA²). Simplifying, we find that the ratio of the radius of wire A to the radius of wire B is one-half, or rA/rB = 1/2.
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Answers
Answer:
change in length is 3.397 cm
Explanation:
Given data
long = 91 m = 9100 cm
coefficient for concrete (a) = 1.2 × 10−5 ( ◦C)−1
temperature = 56 F = (56× 5/9) ◦C
to find out
how much spacing is needed to allow
solution
we know allow space is given by this formula
change in length = coefficient for concrete × given length × temperature .............1
put all value in equation 1
change in length = 1.2 × 10−5 × 9100 × (56× 5/9)
change in length = 3.397 cm
so change in length is 3.397 cm
Energy decreases with decreasing wavelength and decreasing frequency.
B.
Energy increases with decreasing wavelength and increasing frequency.
C.
Energy increases with decreasing wavelength and decreasing frequency.
D.
Energy decreases with increasing wavelength and increasing frequency.
Answers
Answer:
B. Energy increases with decreasing wavelength and increasing frequency.
Explanation:
Answers
Answer:
Minimum capacitance = 200 μF
Explanation:
From image B attached, we can calculate the current flowing through the capacitors.
Thus;
Since V=IR; I = V/R = 5/500 = 0.01 A
Maximum charge in voltage is from 5V to 4.9V. Thus, each capacitor will have 2.5V. Hence, change in voltage(Δv) for each capacitor will be ; Δv = 0.05 V
So minimum capacitance will be determined from;
i(t) = C(dv/dt)
So, C = i(t)(Δt/Δv) = 0.01[0.001/0.05]
C = 0.01 x 0.0002 = 200 x 10^(-6) F = 200 μF
(b) the total work done on it,
(c) the work done by the gravitational force on the crate, and
(d) the work done by the pull on the crate from the rope?
(e) Knowing that the crate is motionless before and after its displacement, use the answers to (b), (c), and (d) to find the work your force F does on the crate.
(f) Why is the work of your force not equal to the product of the horizontal displacement and the answer to (a)?
Answers
Answer:
(a) magnitude of F = 797 N
(b)the total work done W = 0
(c)work done by the gravitational force = -1.55 kJ
(d)the work done by the pull = 0
(e) work your force F does on the crate = 1.55 kJ
Explanation:
Given:
Mass of the crate, m = 220 kg
Length of the rope, L = 14.0m
Distance, d = 4.00m
(a) What is the magnitude of F when the crate is in this final position
Let us first determine vertical angle as follows
=>
=> =
Now substituting thje values
=> =
=>
=>
=>
Now the tension in the string resolve into components
The vertical component supports the weight
=>
=>
=>
=>
=>
=>T =2391N
Therefore the horizontal force
F = 797 N
b) The total work done on it
As there is no change in Kinetic energy
The total work done W = 0
c) The work done by the gravitational force on the crate
The work done by gravity
Wg = Fs.d = - mgh
Wg = - mgL ( 1 - Cosθ )
Substituting the values
=
=
=
=
=
= -1552.55 J
The work done by gravity = -1.55 kJ
d) the work done by the pull on the crate from the rope
Since the pull is perpendicular to the direction of motion,
The work done = 0
e)Find the work your force F does on the crate.
Work done by the Force on the crate
WF = - Wg
WF = -(-1.55)
WF = 1.55 kJ
(f) Why is the work of your force not equal to the product of the horizontal displacement and the answer to (a)
Here the work done by force is not equal to F*d
and it is equal to product of the cos angle and F*d
So, it is not equal to the product of the horizontal displacement and the answer to (a)
model and the actual car?
A: 5:1
B: 1:50
C: 50:1
D: 1:5
Answers
Answer:
it is B 1:50
Explanation:
just did it on apex
Final answer:
The ratio that shows the relationship between the sizes of the model car and the actual car is 1:50. This is because the actual car is 50 times longer than the model car.
Explanation:
The relationship between the sizes of the model car and the actual car is represented by a ratio. To find this ratio, we can divide the length of the actual car by the length of the model car. So, 6 m / 0.12 m = 50. This means that the actual car is 50 times longer than the model car, or in other words, the model car is 1/50th the size of the actual car. Therefore, the correct ratio is 1:50.
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