Europa, a satellite of Jupiter, is believed to have an ocean of liquid water (with the possibility of life) beneath its icy surface. Europa is 3130 km in diameter and has a mass of 4.78×10²² kg. In the future, we will surely want to send astronauts to investigate Europa.In planning such a future mission, what is the fastest that such an astronaut could walk on the surface of Europa if her legs are 0.960 m long?

Answers

Answer 1
Answer:

Answer:

1.12 m/s

Explanation:

We are given that

Diameter of Europa=d=3130 Km

Radius of Europa =r=(d)/(2)=\fra{3130}{2}=1565 Km=1565* 10^3 m

1 km=10^3 m

Mass of Europa,m=4.78* 10^(22) kg

We have to find the velocity of astronaut on the surface of Europa if her legs are 0.960 m long.

d=0.960 m

Acceleration due to gravity on the surface of Europa

g=(GM)/(r^2)

Where G=6.67* 10^(-11)Nm^2/kg^2

Substitute the values

a=(6.67* 10^(-11)* 4.78* 10^(22))/((1565* 10^3)^2)

g=1.3 m/s^2

v=√(gd)=√(1.3* 0.960)=1.12 m/s


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A transverse wave on a string is modeled with the wave function y(x,t) = (0.20 cm) sin (2.00 m^-1 x - 3.00 s^-1 t + pi/16) What is the height of the string with respect to the equilibrium position at a position x = 4.00m and a time t = 10.00 s a. -0.037 cm
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Answers

Answer:

Explanation:

y = (0.2 cm) Sin(2x - 3 t + π/16)

Put x = 4 m, t = 10 s

y = (0.2 cm) Sin (2 x 4 - 3 x 10 + π/16)

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Final answer:

The given wave function represents a transverse wave on a string. Substituting the given values into the wave function yields a height of -0.037 cm. The correct option is a. -0.037 cm.

Explanation:

The given wave function y(x,t) represents a transverse wave on a string. To find the height of the string with respect to the equilibrium position at a position x = 4.00m and a time t = 10.00s, substitute these values into the wave function. y(4.00m, 10.00s) = (0.20 cm) sin[(2.00 m-1)(4.00m) - (3.00 s-1)(10.00s) + π/16].

Calculating this expression gives the height of the string as -0.037 cm. Therefore, the correct option is a. -0.037 cm.

Learn more about Wave Function on a String here:

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Answers

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Answers

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Answers

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