The difference of a number h and 8 is greater than 12 and less than 22

Answers

Answer 1

Answer:

Answer:

12<|h-8|<22

Step-by-step explanation:

Answer 2

Answer: If H is 19 it will be the smallest number the variable H can possibly be to be greater than 12 less than 22 since that is equivalent to 10.

-sorry if wrong
Written by 7th grader

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5x5x5x5= ______ to the power of _____

What are the integers of 171

Answers

Answer:

56, 57, and 58.

Step-by-step explanation:

What’s the correct answer for this?

Answers

Answer:

If I had to guess

Step-by-step explanation:

I would say 11 degree or 90 degree.

Sorry if I am wrong. :_;

Answer:90 degrees

Step-by-step explanation:

In the past, 44% of those taking a public accounting qualifying exam have passed the exam on their first try. Latterly, the availability of exam preparation books and tutoring sessions may have improved the likelihood of an individual’s passing on his first try. In a sample of 250 recent applicants, 130 passed on their first attempt. At the 0.05 level of significance, what is the calculated value of test statistic? (Specify your answer to the 2nd decimal.)

Answers

Answer:

The calculated value of test statistic is z=2.48.

This has a P-value of P=0.00657.

If we state the null hypothesis $H_0: \pi\leq0.44$ at a significance level of $\alpha=0.05$ , we would reject this null hypothesis as $P-value<\alpha$ .

Step-by-step explanation:

We have in this problem, a hypothesis test of proportions.

The test statistic for this is the z-value, and is calculated like that:

$z=(p-\pi-0.5/N)/(\sigma)$

Where the term 0.5/N is the correction for continuity and is negative in the cases that p>π.

p: proportion of the sample; π: proportion of the population; σ: standard deviation of the population.

The standard deviation of the population has to be calculated as:

$\sigma=\sqrt{(\pi(1-\pi))/(N) } =\sqrt{(0.44(1-0.44))/(250) }=√(0.0009856)=0.0314$

The proportion of the sample (p) is $p=130/250=0.52$ .

Then, the test statistic z is

$z=(p-\pi-0.5/N)/(\sigma)=(0.52-0.44-0.5/250)/(0.0314) =(0.078)/(0.0314) =2.48$

The P-value of this statistic is P(z>2.48)=0.00657

If we state the null hypothesis $H_0: \pi\leq0.44$ at a significance level of $\alpha=0.05$ , we would reject this null hypothesis as $P-value<\alpha$ .

The percent of fat calories that a person consumes each day is normally distributed with a mean of 35 and a standard deviation of 10. Suppose that 16 individuals are randomly chosen. Let X = average percent of fat calories. (a) For the group of 16 individuals, find the probability that the average percent of fat calories consumed is more than thirty-seven. (Round your answer to four decimal places.) b) Find the first quartile for the average percent of fat calories. (Round your answer to two decimal places.) percent of fat calories

Answers

Answer:

a) 0.2119 = 21.19% probability that the average percent of fat calories consumed is more than thirty-seven.

b) The first quartile for the average percent of fat calories is 33.31

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = (\sigma)/(√(n))$

In this problem, we have that:

$\mu = 35, \sigma = 10, n = 16, s = (10)/(√(16)) = 2.5$

(a) For the group of 16 individuals, find the probability that the average percent of fat calories consumed is more than thirty-seven. (Round your answer to four decimal places.)

This is the 1 subtracted by the pvalue of Z when X = 37. So

$Z = (X - \mu)/(\sigma)$

By the Central Limit Theorem

$Z = (X - \mu)/(s)$

$Z = (37 - 35)/(2.5)$

$Z = 0.8$

$Z = 0.8$ has a pvalue of 0.7881

1 - 0.7881 = 0.2119

0.2119 = 21.19% probability that the average percent of fat calories consumed is more than thirty-seven.

b) Find the first quartile for the average percent of fat calories. (Round your answer to two decimal places.) percent of fat calories

The 1st quartile is the 25th percentile. So this is the value of X when Z has a pvalue of 0.25. So it is X when Z = -0.675. So

$Z = (X - \mu)/(s)$

$-0.675 = (X - 35)/(2.5)$

$X - 35 = -0.675*2.5$

$X = 33.31$

The first quartile for the average percent of fat calories is 33.31

PLEASE HELP QUICK I NEED IT TO PASS. PLEASE SHOW STEPS, AND DON'T SPAM LINK PLEASE HELP. I NEED SOME HELP

Answers

Answer: 151

Step-by-step

you need to first find the area of each piece of the tent

the 2 rectangular flaps would be 6*8= 48 each

the bottom would be 4*8=32

to find the area of the triangular pieces we need to know the height of each triangle, right now we only know sides. To find the height (the altitude) you draw a line straight down to make a 90 degree angle.

that will also cut your base in half (2 instead of 4) and make 6 your hypotenuse

now use the Pythagorean theorem to find the height of the triangle

$a^(2) +b^(2) =c^(2) \n\na^(2) +2^(2) =6^(2) \na^(2) +4=36\na^(2) =32\na=√(32) = 5.66$

Area of a triangle is

$(1)/(2) bh\n(1)/(2) (4)(5.66)= 11.31$

the area of one triangle is 11.31

so together it is 48+48+32+11.31+11.31= 150.6

round up to 151

In art class students are mixing blue and red paint to make purple paint. Cai mixes 5 cups of blue paint and 6 cups of red paint. Casho mixes 2 cups of blue paint and 3 cups of red paint. Use Cai and Casho’s percent of blue paint to determine whose purple paint will be bluer.

Answers

Answer:

Cai's Would Be Bluer

Step-by-step explanation:

Since 2/5 is 40% and 5/11 is 45% Cai's would be bluer!

Final answer:

Cai's paint will be bluer because she used a higher percentage of blue paint (45.45%) in her mix compared to Casho who used 40% blue paint.

Explanation:

In order to determine whose paint mix will be bluer, we must compare the ratio of blue to red paint in each student's mix. Cai mixes 5 cups of blue and 6 cups of red paint. Casho mixes 2 cups of blue and 3 cups of red paint. We find the percentage of blue paint by dividing the amount of blue paint by the total amount of paint and then multiplying by 100. For Cai, it would be (5 / (5 + 6)) * 100 = 45.45% blue. For Casho, it would be (2 / (2 + 3)) * 100 = 40% blue. Thus, Cai's purple paint will be bluer because it has a higher percentage of blue paint.

Learn more about Percentage here:

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