What must exist for electric charges to flow?
Answers
Answer:electric potential difference
Explanation:
Related Questions
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A 55kg female bungee jumper fastens one end of the cord (made of elastic material) to her ankle and the other end to a bridge. Then she jumps off the bridge. As the cord is stretching it exerts an elastic force directed up on her. Calculate her acceleration at the instant the chord exerts an elastic force of 825N [up] on her.
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Answers
The rocket launches when the countdown reaches "T minus 0." "T" represents the time remaining until a specific event.
What does "T" symbolize in rocket launch countdowns?
In the context of rocket launches, "T" represents time. The countdown begins with "T minus" indicating the time remaining until liftoff. As the countdown progresses, the value of "T" decreases, counting down to zero, which marks the exact moment of launch.
Once the rocket is airborne, the countdown transitions to "T plus," denoting the time elapsed since liftoff. This standardized countdown terminology allows mission control to communicate crucial timing information precisely and efficiently during various phases of the rocket's journey.
Read more about rocket launch
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Answer: The "T" in rocket launch
Explanation:
This tells the Mission Control What will be happening
Answers
The answer would be furnace.
Answer:
the correct answer is furnace
b. Yes, the force applied is parallel to the direction of motion.
c. No, the force applied is perpendicular to the direction of motion.
d. Yes, the force applied is perpendicular to the direction of motion.
Answers
Answer:
No, the force applied is perpendicular to the direction of motion.
Explanation:
Work done is given by :
F = force
d = displacement
= angle between force and displacement
Work is positive when the force and the displacement are in same direction. Work is negative when the force and the displacement are in opposite direction. When the force and displacement are perpendicular to each other, no work is done.
If we carry a book across the room at a constant velocity, the work done is zero. This is because our weight is acting vertically downward and we are moving forward. The angle between the force and the displacement is 90. So, no work is done.
Hence, the correct option is (c) "No, the force applied is perpendicular to the direction of motion".
at a constant velocity?
The force applied is perpendicular to the direction of motion. (C)
b. chronology.
c. discovery.
d. use and applications.
Answers
Answers
Wave speed = (frequency) x (wavelength)
= (0.3 Hz) x (5 m)
= 1.5 m-Hz = 1.5 m/s .
whats the magnitude in N ?
(b) Find the centripetal acceleration of the electron.
whats the magnitude in m/s2
Answers
the electron and proton, and then we need to know the electron's mass.
I'm beginning to get the creepy feeling that, in return for the generous
5 points, you also want me to go and look these up so I can use them
in calculations ... go and collect my own straw to make the bricks with,
as it were.
Ok, Rameses:
Elementary charge . . . . . 1.6 x 10⁻¹⁹ coulomb
negative on the electron
plussitive on the proton
Electron rest-mass . . . . . 9.11 x 10⁻³¹ kg
a). The force between two charges is
F = (9 x 10⁹) Q₁ Q₂ / R²
= (9 x 10⁹ m/farad) (-1.6 x 10⁻¹⁹C) (1.6 x 10⁻¹⁹C) / (5.35 x 10⁻¹¹m)²
= ( -2.304 x 10⁻²⁸) / (5.35 x 10⁻¹¹)²
= 8.05 x 10⁻⁸ Newton .
b). Centripetal acceleration =
v² / r .
A = (2.03 x 10⁶)² / (5.35 x 10⁻¹¹)
= 7.7 x 10²² m/s² .
That's an enormous acceleration ... about 7.85 x 10²¹ G's !
More than enough to cause the poor electron to lose its lunch.
It would be so easy to check this work of mine ...
First I calculated the force, then I calculated the centripetal acceleration.
I didn't use either answer to find the other one, and I didn't use " F = MA "
either.
I could just take the ' F ' that I found, and the 'A' that I found, and the
electron mass that I looked up, and mash the numbers together to see
whether F = M A .
I'm going to leave that step for you. Good luck !