If 842 grams of sodium hydroxide reacts with 750.0 grams of aluminum, how many grams of aluminum hydroxide should theoretically form?

Answers

Answer 1
Answer:

548.55 grams of aluminum hydroxide should theoretically form.

Explanation:

Balanced equation for the reaction:

3 NaOH + Al ⇒ Al(OH)3 +3 Na

DATA GIVEN:

mass of NaOH = 842 grams, atomic mass =39.9 grams/mole

mass of Al = 750 grams, atomic mass = 26.9 grams/mole

aluminum hydroxide theoretical yield = ?

Moles of NaOH reacted

number of moles = (mass)/(atomic mass of 1 mole)

putting the values in the equation

NaOH = (842)/(39.9)

           = 21.1 MOLES OF NaOH

Al = (750)/(26.9)

   = 27.8 moles

from the equation

 from 3 moles of NaOH 1 mole of Al(OH)3 is produced

21.1 moles of NaOH will react to give x moles of Al(OH)3

(1)/(3) = (x)/(21.1)

7.03 moles of Al(OH)3 is formed.

and

1 mole of Al(OH)3 is formed from 1 mole of Al in the reaction

so, 27.8 Moles will react to give give 27.8 moles of Al(OH)3 limiting reagent of the given reaction is NaOH

mass of Al(OH)3 =7.03 x 78 (atomic mass of Al(OH)3)

          = 548.55 grams

theoretical  yield from the given data is 548.55 grams


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Write your answer in scientific notation and Stanford form.(1.2 *  {10}^(7))(4 * {10}^( - 2))

Answers

The answer is 4.8 x 10^5 in scientific notation and 480,000 in standard form.

To multiplying numbers in scientific notation, you need to multiply the coefficients and add the exponents.

Using the given numbers, (1.2 x 107) and (4 x 10-2), we multiply the coefficients 1.2 and 4 to get 4.8.

Then, we add the exponents 7 and -2 to get 5.

Writing the result in scientific notation, we have 4.8 x 105.

In standard form, this is expressed as 480,000.

Therefore, the answer in scientific notation is 4.8 x 105 and in standard form is 480,000.

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1.2 x 10000000 = 12000000
4 x .10 = .4
12000000 x .4 = 4,800,000
= 4.8 x 10^6
The little numbers after the 10 tells you how many times you move the numbers decimal. We do this so we can simplify bigger numbers.

Which of the following best describes how attractive forces of the molecules in a solid compared to a liquid?A)The attractive forces are the same in a solid and liquid
B) The attractive forces are stronger in a liquid
C) The attractive forces are stronger in a solid
D)The attractive forces of a solid allow the particle to move freely while the liquid molecules vibrate around a fixed point

Answers

Answer:

           Option-C (The attractive forces are stronger in a solid)

Explanation:

                   The substance either exist as a Solid or Liquid depends upon on the following two factors;

       ii)  Kinetic Energy:

                                      Greater the K.E of particles, greater will be the distance between the particles of a substance. In Liquids the K.E of particles is greater than the K.E of particles in Solid. Hence, the Liquid Particles separated by greater distance as compared to particles of Solids.

       ii)  Attractive Intermolecular Forces:  

                                                                    Greater the Attractive Intermolecular Forces between the particles of a substance, smaller will be the distance between the particles. As the distance between the particles in Solid state of substance are very small as compared to that of Liquids hence, it can be concluded that the Attractive Intermolecular Forces in Solids are stronger than Liquids.

Can aromatic compounds belong to other classes of compounds

Answers

Answer:

Yes

Explanation:

First of all, aromatic compounds are part of a group of compounds known as hydrocarbons. Hydrocarbons are compounds containing only gmhydrogen and carbon. Some aromatic compounds contain more than one benzene ring. These belong to another subgroup known as poly nuclear aromatic hydrocarbons.

Yes , it is possible for aromatic compounds to belong to other classes of compounds.

QUICK!!!20 POINTS + BRAINLIEST!!!How to test whether a vegetable or fruit can conduct electricity?

Answers

Using a *MULTIMETER* is the best way to test and compare each fruit and vegetable. Because each fruits or vegetables all have different conductivity levels!

(Mark this as the brainliest if this helps!)

When a solution is basic, the pOH is always less than
8, 14, 7

Answers

Answer:

it should be greater than 7 but equal to or less than 14

Explanation:

greater than 8 okay

If it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution, what is the concentration of the NaOH solution? (Round answer to 4 decimal places) *

Answers

Answer:

Concentration of NaOH= 0.0036 M

Explanation:

Given data:

Volume of HCl  = 25 mL

Concentration of HCl = 0.05 M

Volume of NaOH = 345 mL

Concentration of NaOH = ?

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Concentration of HCl

V₁ = Volume of HCl

C₂ = Concentration of NaOH

V₂ = Volume of NaOH

Now we will put the values in formula.

C₁V₁ = C₂V₂

0.05 M × 25 mL =  C₂ × 345 mL

1.25 M.mL = C₂ × 345 mL

C₂ = 1.25 M.mL/345 mL

C₂ = 0.0036 M

Final answer:

To find the concentration of the NaOH solution, we can use the concept of titration. By using the equation Moles = Concentration * Volume, we can calculate the moles of HCl used and then use the ratio of moles between HCl and NaOH to find the concentration of the NaOH solution.

Explanation:

To find the concentration of the NaOH solution, we need to use the concept of titration. From the given information, it takes 25 mL of 0.05 M HCl to neutralize 345 mL of NaOH solution. We can use the equation Moles = Concentration * Volume to find the amount in moles of HCl used. Then, we can use this information to calculate the concentration of the NaOH solution.

First, let's calculate the moles of HCl used:

Moles of HCl = (0.05 M) x (0.025 L) = 0.00125 mol

Next, we can use the ratio of moles between HCl and NaOH, which is 1:1, to find the moles of NaOH in the solution:

Moles of NaOH = 0.00125 mol

Finally, we can calculate the concentration using the formula:

The concentration of NaOH = (0.00125 mol) / (0.345 L) = 0.00362 M

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