What is the momentum of a 2500-kg car traveling at 4.92 m/s?
Answers
Momentum = mass times velocity
mass = 2500kg
velocity = 4.92 m/s
Therefore momentum = 2500 x 4.92
= 12300 Kg m/s
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Answers
Answers
Answer: 3m/s^2
Explanation:
Given that:
Acceleration of object = ?
Force = 9 N
Mass of object = 3 kg
Since force is the product of the mass of an object and the acceleration by which it moves i.e Force = mass x acceleration
9N = 3kg x acceleration
Acceleration = 9N/3kg
Acceleration = 3m/s^2 (3 metres per second square)
Thus, an acceleration of 3m/s^2 is produced.
Transfer stain
Impact stain
Active stain
Answers
Answers
In vacuum and empty space, it's 299,792,458 meters per second
(186,282.4 miles per second).
In any material stuff, it's somewhat less. How much less depends on
what stuff it is ... it's different in each material "medium".
A. slope of the line on the graph
B. length of the line on the graph
C. spacing of the numbers on the time axis
D. spacing of the numbers on the speed axis
Answers
Answer:
A?
Explanation:
b. How high did the arrow go?
c. How long is the arrow in the air?
Answers
a) The velocity of the arrow at its peak is zero
b) The maximum height of the arrow is 31.9 m
c) The time of flight is 5.10 s
Explanation:
a)
The motion of the arrow fired straight upward into the air is a uniformly accelerated motion, with constant acceleration (acceleration of gravity) towards the ground.
The initial velocity of the arrow when it is fired is upward: since the acceleration is downward, this means that as the arrow moves upward, its velocity decreases in magnitude.
Eventually, at some point, the velocity of the arrow will become zero, and then it will change direction (downward) and will start increasing in magnitude. The moment when the velocity raches zero corresponds to the peak of the trajectory of the arrow: therefore, at the peak the velocity is zero.
b)
Since the motion of the arrow is a uniformly accelerated motion, we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the arrow, we have:
u = 25 m/s
v = 0 (when the arrow reaches the peak)
(negative because downward)
s is the maximum height reached by the arrow
And solving for s,
c)
In order to find the time it takes for the arrow to reach the maximum height, we use the following suvat equation:
where here we have:
v = 0 is the final velocity at the peak
u = 25 m/s
And solving for t,
This is the time the arrow takes to reach the top of the trajectory: therefore, the total time of flight is twice this value,
Learn more about accelerated motion:
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