Suppose that two cards are randomly selected from a standard​ 52-card deck. ​(a) What is the probability that the first card is a clubclub and the second card is a clubclub if the sampling is done without​ replacement? ​(b) What is the probability that the first card is a clubclub and the second card is a clubclub if the sampling is done with​ replacement?

Answers

Answer 1
Answer:

Answer:

(a)(1)/(17) (b) (1)/(16)

Step-by-step explanation:

GIVEN: Suppose that two cards are randomly selected from a standard​ 52 card deck.

TO FIND: (a) What is the probability that the first card is a club and the second card is a club if the sampling is done without​ replacement? ​(b) What is the probability that the first card is a club and the second card is a club if the sampling is done with​ replacement.

SOLUTION:

(a)

Probability that first card is club P(A)=\frac{\text{total club cards}}{\text{total cards}}

                                                   =(13)/(52)

                                                   =(1)/(4)

As sampling is done without replacement.

probability that second card is club  P(B)=\frac{\text{total club cards}}{\text{total cards}}

                                                            =(12)/(51)

                                                            =(4)/(17)

Probability that first card is club and second card is club =P(A)* P(B)

                                                                                             =(1)/(4)*(4)/(17)=(1)/(17)

(b)

Probability that first card is club P(A)=\frac{\text{total club cards}}{\text{total cards}}

                                                   =(13)/(52)

                                                   =(1)/(4)

As sampling is done with replacement.

probability that second card is club  P(B)=\frac{\text{total club cards}}{\text{total cards}}

                                                            =(13)/(52)

                                                            =(1)/(4)

Probability that first card is club and second card is club =P(A)* P(B)

                                                                                             =(1)/(4)*(1)/(4)=(1)/(16)


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a new recipe calls for 1/3 cups sugar and you have 2 1/3 cups in the pantry if you have unlimited supplies of the other ingredients how many recipes could you make? PLS HELP ​

Answers

Answer:

7 recipes could be made with 2(1)/(3) cups of sugar.

Step-by-step explanation:

Quantity of sugar required for a recipe =(1)/(3) cups

Quantity of sugar required in a pantry =2(1)/(3) cups

Here,

2(1)/(3)=(7)/(3)

So,

Quantity of sugar required in a pantry =(7)/(3) cups

Number of recipes that could be made  =((7)/(3) )/((1)/(3) ) =7

Therefore, 7 recipes could be made with 2(1)/(3) cups of sugar.

Find the equation of a line through (1,1) whichisperpendicular to a line through (1,3) and (2,5).

Answers

Answer:

y=(-1)/(2)x+(3)/(2)

Step-by-step explanation:

Point on a line is  (1,3) and (2,5).

slope=(y_2-y_1)/(x_2-x_1) =(5-3)/(2-1) =2

slope of given line is 2

slope of perpendicular lines are negative reciprocal of one another

slope of perpendicular line is -1/2

slope = -1/2     (1,1)

y-y_1=m(x-x_1)

y-1=(-1)/(2)(x-1)

y-1=(-1)/(2)x+(1)/(2))

add 1 on both sides

y=(-1)/(2)x+(3)/(2)

9,16,25,36 arithmetic or geometric?24,18,12,arithmetic or geometric?
500,100,20 ,4 arithmetic or geometric?

Answers

Answer:

9,16,25,36 neither, 24,18,12 arithmetic, 500,100,20 ,4 geometric

Step-by-step explanation:

1. has no common number

2. goes down by 6 each time

3. is divided by 5 each time

consider the ratio of 153 per 108. write this ratio in different forms. a ratio written as a reduced fraction and as a decimal rounded to the hundredths.

Answers

1.42 is the approximate value of the ratio (153)/(108).

What is the ratio?

The ratio is the number of times one value contains or is contained within the other in a quantitative relationship between two numbers.

What is the required answer?

The ratio of 153:108 is given.

Other forms of the ratio are

(153)/(108)=(17)/(12)

=1.41666...\approx 1.42 (rounded to the hundredth place.

Learn more about ratios in- brainly.com/question/13419413?referrer=searchResults

#SPJ2

Answer:

153:108

1.42

1 (5)/(12)

I am not understanding this question.

Answers

Answer:

boardgamegeek.com/boardgame/245655/kings-dilemma

Step-by-step explanation:

A​ person's blood pressure is monitored by taking 8 readings daily. The probability distribution of his reading had a mean of 129 and a standard deviation of 7. a. Each observation behaves as a random sample. Find the mean and the standard deviation of the sampling distribution of the sample mean for the eight observations each day. b. Suppose that the probability distribution of his blood pressure reading is normal. What is the shape of the sampling​ distribution? c. Refer to​ (b). Find the probability that the sample mean exceeds 140.

Answers

Answer:

a) \mu_(\bar X)= 129

\sigma_(\bar X)= (7)/(√(8))=2.475

b) If the distribution is normal then the sampling distribution would be bell shaped and normal

c) P(\bar X >140)

And we can use the z score formula given by:

z =(\bar X -\mu)/(\sigma_(\bar X))

And replacing we got:

z =(140-129)/(2.475)= 4.44

And then we can find the probability using the complement rule and the normal standard distribution or excel and we got:

P(\bar X>140) = P(Z>4.44) =1-P(z<4.44) \approx 0

Step-by-step explanation:

For this case we have the following info:

n=8 represent the sample size

\bar X=129 the sample mean

s=7 the standard deviation

Part a

If we assume that the distirbution is bell shaped then we can find the parameters like this:

\mu_(\bar X)= 129

\sigma_(\bar X)= (7)/(√(8))=2.475

Part b

If the distribution is normal then the sampling distribution would be bell shaped and normal

Part c

We want this probability:

P(\bar X >140)

And we can use the z score formula given by:

z =(\bar X -\mu)/(\sigma_(\bar X))

And replacing we got:

z =(140-129)/(2.475)= 4.44

And then we can find the probability using the complement rule and the normal standard distribution or excel and we got:

P(\bar X>140) = P(Z>4.44) =1-P(z<4.44) \approx 0