Answer:
The list of event (pulling a face card,F or a number card, N) that correctly makes up the sample space when a card is drawn without replacement is;
FF
FN
NF and
NN
Step-by-step explanation:
Here we have the definition of a sample space as one which has all possible outcomes
Therefore, the list of events that correctly makes up the sample space of events when you pull out two cards we have either a face card F or a number card N, and the sample space is;
FF
FN
NF and
NN
Where the likelihood of each outcome changes as the number of face cards and number card changes as each card is drawn without replacement.
Answer:
just took the test, the correct answer is:
B) two number cards, two face cards, one number card and one face card
B. (82)
C. (83)
D. 4(82
Answer:a
Step-by-step explanation:
MRI machine
Waist measurement
Weight measurement
It is Bioelectrical impedance machine, these devices are used to measure the percentage of fat on your body so it is B
Bioelectrical impedance machine
That is definitely the answer, so A not B
what is the vertex function of
y=-3(x - 1)² +2
The length of the rectangle is 15 dm and the width is 13 dm.
Let's assume that the length of the rectangle is "L" and the width is "W".
From the problem statement, we have two pieces of information:
The area of the rectangle is 195 dm²:
Area = Length x Width
195 dm² = L x W
The width is two less than the length:
W = L - 2
Now, we can substitute the second equation into the first equation to eliminate W and get an equation with only one variable:
195 dm² = L x (L - 2)
Simplifying the equation:
195 dm² = L² - 2L
L² - 2L - 195 dm² = 0
To solve for L, we can use the quadratic formula:
L = (-b ± √(b² - 4ac)) / 2a
Where a = 1, b = -2, and c = -195.
L = (2 ± √(2² + 4 x 1 x 195)) / 2 x 1
L = (2 ± √4 + 780) / 2
L = (2 ± √784) / 2
L = (2 ± 28) / 2
L = 15 or L = -13
Since the length can't be negative, the length of the rectangle is L = 15 dm.
Now we can use the equation W = L - 2 to find the width:
W = 15 dm - 2 dm
W = 13 dm
Therefore, the length of the rectangle is 15 dm and the width is 13 dm.
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Answer:
The highest common factor would be 114
3876 = 2x3x3x17x19
114 = 2x3x19
The highest common factor (HCF) of 3876 and 114 is 6.
To find the highest common factor (HCF) of two numbers, such as 3876 and 114, we need to determine the largest number that divides evenly into both given numbers.
We can start by finding the prime factors of each number. The prime factorization of 3876 is 2 × 3 × 1,29, and the prime factorization of 114 is 2 × 3 × 19.
The common factors we can identify are 2 and 3, so the HCF of 3876 and 114 is 2 × 3, which is 6.
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