CHEMISTRY MIDDLE SCHOOL

What is the concentration of O2(g), in parts per million, in a solution that contains 0.008 gram of O2(g) dissolved in 1000. grams of H2O(2)?Listen

1

0.8 ppm

8 ppm

80 ppm

800 ppm

Answers

Answer 1
Answer:

Answer : The concentration of O_2 (g) in parts per million is, 8 ppm

Explanation : Given,

Mass of oxygen gas (solute) = 0.008 g

Mass of water (solvent) = 1000 g

First we have to calculate the mass of solution.

Mass of solution = Mass of solute + Mass of solvent = 0.008 + 1000 = 1000.008 g

Now we have to calculate the concentration of  O_2 (g) in parts per million.

ppm : It is defined as the mass of solute present in one million (10^6) parts by mass of the solution.

ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}* 10^6

Now put all the given values in this expression, we get

ppm=(0.008g)/(1000.008g)* 10^6=7.99=8ppm

Therefore, the concentration of O_2 (g) in parts per million is, 8 ppm

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I hope this helps a little ! :)

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PLEASE HELP!!!A student mixed two clear liquids together in a beaker and a solid precipitate formed. His data is shown below:
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Liquid reactant B: 17 g
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Answers

This might be right. Im not quite sure. This is what my 5th grade science teacher told me. 'Look at the 2 LR's and add them together. Then look at the total amount which is 32. When you add the 2 LR's you get 17. So subtract 17 from 32 and you get 15. So: C:15 is your answer." (LR's stands for liquid reactants)

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Total amount is 32

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