Which expression has a negative value?−3×3×−3×−3×−3

−3×−3×3

−3×3×−3×−3

−3×−3

Answer:

c

Step-by-step explanation:

Answer:

C. 2•2•2•2•2•2

Step-by-step explanation:

Exponents show how many times a number is being multiplied by itself.

For you would have to multiply 2 by itself 6 times. Thus getting 64 in the end.

The particle passes through the origin at t = 0 and t = ±√20. The particle is instantaneously motionless at t = 0 and t = ±√10.

(a) To determine the times at which the particle passes through the origin, we need to find when the position function equals zero. So, we set s(t) = 0 and solve for t.
t4 - 20t2 = 0
Factoring out a t2, we get:
t2(t2 - 20) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial position), and t = ±√20 (approximately t = ±4.47).

(b) To determine when the particle is instantaneously motionless, we need to find when the velocity of the particle is equal to zero. The velocity function of the particle is the derivative of the position function. So, we differentiate s(t) with respect to t to find the velocity function.
v(t) = s'(t) = 4t³ -40t
Setting v(t) = 0, we have:
4t³ -40t = 0
Factoring out a 4t, we get:
4t(t² - 10) = 0
Setting each factor equal to zero and solving for t gives us the following solutions:
t = 0 (giving us the initial velocity), and t = ±√10 (approximately t = ±3.16).

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Final answer:

The particle passes through the origin at t = 0 and t = √20 seconds. The particle is instantaneously motionless at t = 0 and t = ±√10 seconds.

Explanation:

The position of the particle at time t is given by the equation s(t) = t4 - 20t2. To determine the times when the particle passes through the origin, we set s(t) equal to zero and solve for t. This gives us the quadratic equation t4 - 20t2 = 0, which can be factored as t2(t2 - 20) = 0. The solutions to this equation are t = 0 and t = ±√20. Since t cannot be negative in this scenario, the particle passes through the origin at t = 0 and t = √20 seconds.

To determine the times when the particle is instantaneously motionless, we need to find the times when the velocity of the particle is equal to zero. The velocity of the particle can be found by taking the derivative of the position function with respect to time, v(t) = 4t3 - 40t. Setting this equation equal to zero and solving for t gives us the cubic equation 4t3 - 40t = 0. This equation can be factored as 4t(t2 - 10) = 0. The solutions to this equation are t = 0 and t = ±√10. Therefore, the particle is instantaneously motionless at t = 0 and t = ±√10 seconds.

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Answer:

C. 150 pages

Step-by-step explanation:

204 divided by 136 = 1.5

1.5 * 100 = 150

Hope it helps! :)

Given Information:

Annual interest rate = r = 12%

Principal amount = P = $1000

Number of years = t = 3  

Required Information

Accumulated amount = A = ?

Answer:

Annual compounding = A = $1404.93

Semi-annuall compounding = A = $1418.52

Quarterly compounding = A = $1425.76

Monthly compounding = A = $1432.30

Daily compounding = A = $1433.14

Step-by-step explanation:

The accumulated amounts in terms of compound interest is given by  

Where  P is the initial amount invested and A is the accumulated amount.

For annual compounding:

i = 0.12

N = 3

For semiannually compounding:

i = 0.12/2 = 0.06

N = 2*3 = 6

For quarerterly compounding:

i = 0.12/4 = 0.03

N = 4*3 = 12

For monthly compounding:

i = 0.12/30 = 0.004

N = 30*3 = 90

For daily compounding:

i = 0.12/365 = 0.0003287

N = 365*3 = 1095

Option D:

is positive product.

Solution:

Some basic rules of product:

If the negative sign is in even number of times then the product is positive.

If the negative sign is in odd number of times then the product is negative.

To find which product is positive:

Option A:

Here, number of negative signs = 3 which is odd

So, the product is negative.

Option B:

Here, number of negative signs = 3 which is odd

So, the product is negative.

Option C:

Here, number of negative sign = 1 which is odd

So, the product is negative.

Option D:

Here, number of negative sign = 2 which is even

So, the product is positive.

Hence option D is the correct answer.

is positive product.

Answer:d’s right

Step-by-step explanation: