MATHEMATICS COLLEGE

Solve the equation.
3* = 27
x=L(Simplify your answer.)

Answers

Answer 1
Answer:

Answer:

3³ = 27

This is because:

3x3x3 = 27
Answer 2
Answer: Your answer would be 3
3x3x3
\/ x 3
9 x 3
\ /
27

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A survey of UF students asked for their employment status and their year in school. The results appear below. yr in school job no job
Freshman 16 22
Sophomore 24 15
Junior 17 20
Senior 25 19
Super Senior 8 5

What is the distribution of the test statistic under the null hypothesis

Answers

Answer:

There is no relationship between your year in school and having a job.

Step-by-step explanation:

In this instance, the chi sq test need to be performed.

Chi sq is used to determine if there is a significant relationship between two categorical variables.

The two variables here are year in school and employment status.

The two variables are independent(no relationship exists)

This implies that there is null hypothesis

Therefore, the Null Hypothesis is

There is no relationship between your year in school and having a job.

I need some help with this calculus 1 implicit diffrention problem?

Answers

Answer:

y" = -24 / y³

Step-by-step explanation:

6x² + y² = 4

Take the derivative of both sides with respect to x.

12x + 2y y' = 0

Again, take the derivative of both sides with respect to x.

12 + 2y y" + y' (2y') = 0

12 + 2y y" + 2(y')² = 0

Solve for y' in the first equation.

2y y' = -12x

y' = -6x/y

Substitute and solve for y":

12 + 2y y" + 2(-6x/y)² = 0

12 + 2y y" + 2(36x²/y²) = 0

12 + 2y y" + 72x²/y² = 0

6y² + y³ y" + 36x² = 0

y³ y" = -36x² − 6y²

y" = (-36x² − 6y²) / y³

Solve for y² in the original equation and substitute:

y² = 4 − 6x²

y" = (-36x² − 6(4 − 6x²)) / y³

y" = (-36x² − 24 + 36x²) / y³

y" = -24 / y³

Simplify x ^8/ x ^6 ​

Answers

Answer:

\displaystyle (x^8)/(x^6) = x^2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Exponential Property [Dividing]: \displaystyle (b^m)/(b^n) = b^(m - n)

Step-by-step explanation:

Step 1: Define

Identify

\displaystyle (x^8)/(x^6)

Step 2: Simplify

  1. Exponential Rule [Dividing]:                                                                             \displaystyle (x^8)/(x^6) = x^(8 - 6)
  2. [Exponents] Subtract:                                                                                       \displaystyle (x^8)/(x^6) = x^(2)

X^2-10x+y^2-20y=-125 what is x+y=?

Answers

The value of x + y from the equationx^2-10x+y^2-20y=-125 is 15

The equation is given as:

x^2-10x+y^2-20y=-125

Add 125 to both sides of the equation

x^2-10x+y^2-20y+125 = 0

Express 125 as 100 + 25

x^2-10x+y^2-20y+100 +25 = 0

Rewrite the equation as:

x^2-10x +25+y^2-20y+100 = 0

Group the expressions

[x^2-10x +25]+[y^2-20y+100 ]= 0

Express the expressions in both groups as perfect squares

(x - 5)^2+(y - 10)^2= 0

Possible equations from the above equation is:

(x - 5)^2= 0 and (y - 10)^2= 0

Take the square roots of both sides

x - 5= 0 and y - 10= 0

Solve for x and y in the above equations

x = 5 and y =10

So, we have:

x + y = 5 + 10

x + y = 15

Hence, the value of x + y is 15

Read more about quadratic functions at:

brainly.com/question/1214333

5a - 3b if a=5 and b=7

Answers

Answer:

5(5) - 3(7) = 4

Josie bought 750 bags of peanuts for $375 he intends to sell each bag for $.15 more than you paid how much should he charge for each bag

Answers

Step-by-step explanation:

Jose bought 750 bags for $375.00

Each bag cost $375/750= $0.50

He  intends to sells them for $0.15 more

He should charge : $0.5 +$0.15=$0.65
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