MATHEMATICS COLLEGE

I need help look at the picture

Answers

Answer 1

Answer:

Answer:

option 1

Step-by-step explanation:

i was just doing that question

Answer 2

Answer: a i was juss doing that question

Related Questions

Find an equation of a line with the x- and y-intercepts below. Use exact fractions when necessary.x-intercept 7; y-intercept -5
Jenny wants to share some stickers with her friends. If she gives each of her friends three stickers, she will have eight stickers left. If she gives each of her friends four stickers, she will need two stickers more. How many stickers does Jenny have?
the cell wall of which out of this is not made up of cellulose bacteria mango tree hydrilla cactus which one is correct
Given that m angle KLH=120^ which statement about the must be true? angle HLM is bisected by angle GLJ is bisected by vec LH . m angle KLG=m angle HLJ m angle HLI=m angle LLM
Kyleigh put a rectangular sticker on her notebook.the hiegth of the sticker measures 18cm.the base is half as long as the height.what is the area of the notebook does the sticker cover

At a college, 69% of the courses have final exams and 42% of courses require research papers. Suppose that 29% of courses have a research paper and a final exam. Let F be the even that a course has a final exam. Let R be the event that a course requires a research paper. (a) Find the probability that a course has a final exam or a research paper. Your answer is : (b) Find the probability that a course has NEITHER of these two requirements. Your answer is :

Answers

Answer:

a) 0.82

b) 0.18

Step-by-step explanation:

We are given that

P(F)=0.69

P(R)=0.42

P(F and R)=0.29.

P(course has a final exam or a research paper)=P(F or R)=?

P(F or R)=P(F)+P(R)- P(F and R)

P(F or R)=0.69+0.42-0.29

P(F or R)=1.11-0.29

P(F or R)=0.82.

Thus, the the probability that a course has a final exam or a research paper is 0.82.

P( NEITHER of two requirements)=P(F' and R')=?

According to De Morgan's law

P(A' and B')=[P(A or B)]'

P(A' and B')=1-P(A or B)

P(A' and B')=1-0.82

P(A' and B')=0.18

Thus, the probability that a course has NEITHER of these two requirements is 0.18.

How to solve this w2-64= by facturing

Answers

Answer: (x+8)(x-8)

Step-by-step explanation:

hope this helped :)

The line that touches a circle at one point is called the

Answers

Answer: Tangent

Explanation: For a circle a tangent is a straight line which touches the circle at only one point. It is also referred to as the line of tangency.

Consider the following hypothesis test. The following data are from matched samples taken from two populations. Population Element 1 2 1 21 20 2 28 26 3 18 18 4 20 20 5 26 24 Compute the difference value for each element. If your answer is "0", enter 0.a. Compose the difference valuefor each element.b. Compute d.c.Compute the standard deviation sd.d.Conduct a hypothesis test using α=.05.What is yourconclusion?

Answers

Answer:

a) d: 1 2 0 0 2

b) $\bar d= (\sum_(i=1)^n d_i)/(n)= (5)/(5)=1$

c) $s_d =(\sum_(i=1)^n (d_i -\bar d)^2)/(n-1) =1$

d) $p_v =P(t_((4))>2.236) =0.0445$

So the p value is lower than the significance level provided, so then we can conclude that we reject the null hypothesis that the difference mean between population 1 and 2 is less than 0. And we can say that the mean difference is higher than 0 at 5% of significance.

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.

Let put some notation

x=Population 1 , y = population 2

x: 21 28 18 20 26

y: 20 26 18 20 24

a. Compose the difference valuefor each element

Let d =x-y, so the values for the difference are:

d: 1 2 0 0 2

b. Compute d.

We need the mean for the difference. If we use the following formula we got:

$\bar d= (\sum_(i=1)^n d_i)/(n)= (5)/(5)=1$

c.Compute the standard deviation sd.

For the standard deviation we can use the following formula:

$s_d =(\sum_(i=1)^n (d_i -\bar d)^2)/(n-1) =1$

d.Conduct a hypothesis test using α=.05.What is yourconclusion?

If we assume that the system of hypothesis for this case are:

Null hypothesis: $\mu_x- \mu_y \leq 0$

Alternative hypothesis: $\mu_x -\mu_y > 0$

We can calculate the statistic given by :

$t=(\bar d -0)/((s_d)/(√(n)))=(1 -0)/((1)/(√(5)))=2.236$

The next step is calculate the degrees of freedom given by:

$df=n-1=5-1=4$

Now we can calculate the p value, since we have a right tailed test the p value is given by:

$p_v =P(t_((4))>2.236) =0.0445$

Final answer:

To complete this hypothesis test, calculate the difference value for each element, compute the sample mean difference (d), calculate the standard deviation (sd), and then conduct the hypothesis test using a significance level of α = 0.05.

Explanation:

To compute the difference value for each element, subtract the second value from the first value for each pair. For example, the difference for the first pair is 1-2 = -1. Repeat this for each pair of elements in the data set.

To compute the sample mean difference (d), add up all the difference values and divide by the total number of pairs. In this case, d = (-1 + 1 + 2 + 0 + 2)/5 = 0.8.

To compute the standard deviation (sd), first calculate the squared difference value for each pair and sum them up. Then divide the sum by (n-1), where n is the total number of pairs. Finally, take the square root of the result. In this case, sd = sqrt(((1-0.8)^2 + (2-0.8)^2 + (0-0.8)^2 + (2-0.8)^2)/4) = 1.32.

For the hypothesis test, we compare the sample mean difference (d) to the population mean difference (μd) under the null hypothesis. The null hypothesis states that there is no difference between the two populations. If the difference between d and μd is statistically significant at a significance level of α = 0.05, we reject the null hypothesis and conclude that there is a significant difference between the two populations. Otherwise, we fail to reject the null hypothesis.

Without information about the population mean difference (μd), we cannot perform the hypothesis test or draw a conclusion.