Daltons dad rode 1 kilometer north 2 kilometers west 1 kilometer south and 2 kilometers east. Dalton rode the same path 5 times . How many kilometers farther did dalton ride?

Answers

Answer 1
Answer:

Answer:

Dalton didn't ride any kilometer farther since he keeps threading in the same path as that of his father.

Step-by-step explanation:

If Dalton's dad rode 1 kilometer north, 2 kilometers west 1 kilometer south and 2 kilometers east, then he has been moving in a rectangular path.

If Dalton rode in the same path 5times, then Dalton's has not move farther than his dad since he is still moving in the same rectangular path. He is only expending more energy.

Their final destination will still be the same for both of them no matter how many times Dalton keeps threading in the same path.

Answer 2
Answer:

Answer:

Step-by-step explanation


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Help please quickly!!!

Answers

Answer:

rotation

Step-by-step explanat

The answer is rotation,hope this helps:)

How do i graph yhe answet

Answers

Answer: open dot starting on the 6 then going down 5,4,3,2,1... with a solid line

Step-by-step explanation:

The vertices of a feasible region are (14, 2), (0, 9), (6, 8), and (10, 3). What is the maximum value of P if P = 180x + 250y?

Answers

For this problem, we must first plot of each point using the given points. Assume that each coordinate given is in the (x,y) form. To get the maximum value, we can plus in each coordinate set to the equation to see which P comes out to be the largest. For (14,2), P=3020. For (0,9), P=2250. For (6,8), P=3080. For (10,3), P=2550. The maximum value for P would be P=3080.

Answer:

It’s C

Step-by-step explanation:

Radius of a clock is 8.5 centimeters. What is circumference of the clock?

Answers

The circumference of a circle is 2\pir
C= 8.5 x 2 x \pi
C= 17 x \pi
C= 53.407 centimeters

Hope this helps :)

Suppose you throw a dart at a circular target of radius 10 inches. Assuming that you hit the target and that the coordinates of the outcomes are chosen at random, find the probability that the dart falls (a) within 2 inches of the center. (b) within 2 inches of the rim. (c) within the first quadrant of the target. (d) within the first quadrant and within 2 inches of the rim.

Answers

Answer:

a) The probability is 0.04

b) The probability is 0.36

c) The pprobability is 0,25

d) The probability is 0.09

Step-by-step explanation:

Lets calculate areas:

the target has a radius of 10 inces, hence the target area has a area on 10²*π = 100π square inches.

a) A circle of 2 inches of radius has an area of 2²π = 4π square inches, hence the probability of hitting that area is 4π/100π = 1/25 = 0.04

b) If the dart s within 2 inches of the rim, then it is not at distance 8 inches from the center (that is the complementary event). The probability for the dart to be at 8 inches of the center is 8²π/100π = 64/100 = 16/25 = 0.64, thus, the probability that the dart is at distance 2 or less from the rim is 1-0.64 = 0.36.

c) The first quadrant has an area exactly 4 times smaller than the area of the target (each quadrant has equal area), thus the probability for the dart to fall there is 1/4 = 0.25

d) If the dart is within 2 inches from the rim (which has probability 0.36 as we previously computed), then it will be equally likely for the dart to be in either of the 4 quadrants (the area that is within 2 inches from the rim forms a ring and it has equal area restricted on each quadrant). Therefore, the probability for the dice to be in the first qudrant and within 2 inches from the rim is 0.36*1/4 = 0.09.

What's the average rate of the graph from x = -2 to x = 0?​

Answers

Answer:

-2

Step-by-step explanation:

I hope this helps you :)

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