As part of a competition Diego must spin around in a circle six times and then run to a tree. The time he spends on each spin is represented by s and the time he spends running is r. He gets to the tree 21 seconds after he starts spinning. Write an equation showing the relationship between s and r.
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Answer:
6s + 2r = 21
Step-by-step explanation:
Please kindly see the attached file for explanaion
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You can't round it to the thousandths place.
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Answer:
a. 1 =ST; 20 = RS;5 = x
b. 40 = ST; 20 = RS; 12 = x
c.17 = RT;6 = RS; 7 = x
d. 34 = RT; 15 = RS; 6 = x
Step-by-step explanation:
___
Since the exercise ONLY tells you that PointSis inbetweenRT,use the SegmentAdditionPostulate for all exercises:
d.8x - 14 = 19 + [4x - 9]
8x - 14 = 10+ 4x(Combine like-terms)
- 8x-8x
___________________
-14 = 10 - 4x
-10-10
_____________
-24 = -4x
________
-4-4
6 = x[Plug this back into the equations above to get these measures: 34 = RT; 15 =RS]
c.x+ 10 = 11 + [2x - 8]
x+10 = 3+ 2x(Combine like-terms)
-2x-2x
________________
-x + 10 = 3
- 10-10
___________
-x= -7
____
-1-1
x = 7 [Plug this back into the equations above to get these measures: 17 = RT; 6 = RS]
b.60 = [4x - 8] + [3x - 16]
60 = 7x-24(Combine like-terms)
+24+ 24
______________
84 = 7x
______
77
12 = x[Plug this back into the equations above to get these measures: 40 = ST; 20 = RS]
a.21 = [x - 4] + [2x + 10]
21 = 3x+6(Combine like-terms)
-6- 6
______________
15 = 3x
______
33
5 = x[Plug this back into the equations above to get these measures: 1 = ST; 20 = RS]
I am delighted to assist you anytime.
To solve for x and find the lengths RS, ST, and RT, we can set up an equation using the given information. Using the equation RS + ST + RT = 0 and substituting the given values, we can simplify the equation to find x. With the value of x, we can then find the lengths RS, ST, and RT. Therefore, RS = -8, ST = -13, and RT = 21.
To write an equation in terms of x, we need to set up an equation using the given information RS = 2x + 10, ST = x - 4, and RT = 21.
We can start by writing the equation RS + ST + RT = 0.
Substituting the given values, we get (2x + 10) + (x - 4) + 21 = 0. Simplifying this equation, we have 3x + 27 = 0.
Solving for x, we subtract 27 from both sides and divide by 3, to get x = -9.
With the value of x, we can now find the lengths RS, ST, and RT. RS = 2(-9) + 10 = -8, ST = (-9) - 4 = -13, and RT = 21.
Therefore, RS = -8, ST = -13, and RT = 21.
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(10÷2)+3
Hope this helps :)
Final answer:
The mathematical expression that represents 'the quotient of 10 and 2, plus 3' is (10 / 2) + 3. According to the order of operations, first 10 is divided by 2 to get 5. Then 5 is added to 3, equaling 8.
Explanation:
The asked expression in Mathematical terms is written as: (10 divided by 2) plus 3. To perform this operation, we first execute the division as per Order of Operations. 10 divided by 2 yields 5. We then add this value to 3 which gives us an answer of 8. Therefore, 'the quotient of 10 and 2, plus 3' translates into the mathematical expression: (10 / 2) + 3 = 8.
The expression that represents the quotient of 10 and 2, plus 3, is (10 ÷ 2) + 3.
First, we divide 10 by 2, which gives us 5. Then, we add 3 to the quotient, resulting in a final answer of 8.
So, the expression is (10 ÷ 2) + 3 = 8.
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Answer:21 students.i hope it helped