1. The force between a pair of charges is 100 newtons. The distance between the charges is 0.01 meter. If one of the charges is 2 u 10-10 C, what is the strength of the other charge?2. The force between two charges is 2 newtons. The distance between the charges is 2 u 10-4 m. If one of the charges is 3 u 10-6 C, what is the strength of the other charge?

Answers

Answer 1
Answer:

Answer:

1. Q = 5.56 * 10^(-3) C

2.Q = 2.97 * 10^(-12) C

Explanation:

1. Electrostatic force is given as:

F = (kqQ)/(r^2)

where k = Coulombs constant

q = charge of first charge

Q = charge of the second charge

r = distance between them

From the question:

F = 100 N

q  = 2 * 10^(-10) C

r = 0.01 m

We need to find Q.

From the formula of force, we have that Q is:

Q = (Fr^2)/(kq)

Q = (100 * 0.01^2)/(8.99 * 10^9 *2 * 10^(-10)) \n\n\nQ = (0.01)/(1.798)\n \n\nQ = 0.00556 C = 5.56 * 10^(-3) C

This is the charge, Q, of the second charge.

2. From the question:

F = 2 N

q  = 3 * 10^(-6) C

r = 2 *10^(-4) m

We need to find Q.

Using the same formula for Q as in 1. above, we have that:

Q = (2 * (2 *10^(-4))^2)/(8.99 * 10^9 *3 * 10^(-6)) \n\n\nQ = (8 * 10^(-8))/(26970)\n \n\nQ = 2.97 * 10^(-12) C

This is the charge, Q, of the second charge.

Answer 2
Answer:

Answer:

(1)  4.4835*10^(17)C

(2)2.9748*10^(-12)C

Explanation:

Force Between two charges is give by.

F=k(Q_1 *Q_2)/(r^2) , here k is called coulomb constant and has value = 8.967*10^9Nm^2/C.

(1) case, F =100N, r = 0.1m and Q_1=2*10^(-10)C substituting these values in above equation and solving for unknown gives us.

Q_2 = 4.4835*10^(17)C.

(2) Case, F = 2N, r = 2*10^(-4)m and Q_1=3*10^(-6)C.

again by substituting these in above equation and solving for unknown gives us.

Q_2=2.9748*10^(-12)C.


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Answers

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Answers

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Compare contrast speed and velocity

Answers


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Answers

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