A bottle of erythromycin suspension contains 250 mg of erythromycin in every 5 mL of suspension. How many grams of erythromycin are in a 200-mL bottle?

Answers

Answer 1
Answer:

Answer:

There are 10g in 200ml bottle

Step-by-step explanation:

See the attached files for explanation.


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What is...
6x-2y=5
3x+2y=-2

Answers

6x-2y=5
x-intercept = 5/6
  y-intercept = 5/-2
3x+2y=-2
 x-intercept = -2/3
  y-intercept = -2/2

Which one is greater 2.857 or 2.87

Answers

Answer:

2.87

Step-by-step explanation:

Find the domain of the function

Answers

For Domain, you just need to watch out for Square Roots and/or Fractions! 1) a POLYNOMIAL (no square roots or fractions), i.e. f(x) = x^2 + 3x + 1, domain is "all real numbers." 2) a FRACTION (w/ no square root), i.e. f(x) = (2x+1)/(x^2+5x+6). Set bottom "not equal" to zero.

Which expressions are equivalent to 16x4 − 64? Check all that apply. 16x4 + 16x – 16x – 64 16x4 – 8x – 8x – 64 (4x2 + 8)(4x2 – 8) 16(x2 + 2)(x2 – 2) 4(4x4 – 8)

Answers

The given expression is 16x^(4)-64.

It can be written as 16x^(4)+16x-16x-64.[ we can add or subtract the same thing]

The expression can be factored as difference of two squares

16x^(4)-64=[4x]^(2)-(8)^(2)=(4x^(2)+8)(4x^(2)-8)

The common factor of the two terms is 16

WE can take 16 as common factor:16x^(4)-64=16[x^(2)-2^(2)]

=16(x^(2)+2)(x^(2)-2)

Options  1 ,3,4 are the equivalent expressions.


16x^4 - 64

equivalent expressions are :
16x^4 + 16x - 16x - 64
(4x^2 + 8)(4x^2 - 8)
16(x^2 + 2)(x^2 - 2)

Write this equation in standard form
9x^2-4y^2-24y-72=0

Answers

9x^2-4y^2-24y-72=0\n \n 9x^2-4y^2-24y=72\n \n 9x^2-(4y^2+24y+36)=72-36\n \n 9x^2-4(y+3)^2=36\n \n (9x^2)/(36)-(4(y+3)^2)/(36)=(36)/(36)\n \n \boxed{(x^2)/(4)-((y+3)^2)/(9)=1}

A student spends no more than 2 hours on his math and English homework. If math takes about twice as long as long as english. How long will the student be able to finish hisEnglish homework?

Answers

E - English homework,  M - Math homework;
M + E ≤ 2 hours
M = 2 E
2 E + E ≤ 2 hours
3 E ≤ 2 hours = 120 minutes
E ≤ 120 : 3 
E ≤ 40 minutes
Answer:
The student will be able to finish his English homework in less or equal to 40 minutes. 

Answer:

d) 2/3

Step-by-step explanation:

Step one: write your equations

"A student spends no more than 2 hours on his math and English homework." Our sign will be less than or equal to. Our operation will be addition since the question used "and" to connect math and English.

m=x; e=y

Equation a. x + y  ≤ 2

Equation b. x = 2y (2y because math takes twice as long, therefore, we can multiply y by 2) Remember: x or y by itself has a coefficient of 1.

Step two: Substitute x into equation a.

x=2y so our new equation is: 2y + y  ≤ 2

Step three: isolate y and solve

2y + y= 3y

3y ≤ 2

Next, isolate y by dividing both sides by 3.

3y/3  ≤ 2/3

y ≤ 2/3

There is your answer, English equals y, so the maximum time he can take on his English work is 2/3 of an hour or 40 minutes.

Full question: A student spends no more than 2 hours on his math and English homework. If math takes about twice as long as English, what is the maximum time that the student can spend on English?