(4r2 – 3r + 2) – (-r2 – 3r) =

8000 because u add an extra 0 if u multiple with a number with a zero or no

Answer:

(a) Approximately 95% of women with platelet counts within 2 standard deviations of the​ mean.

(b) Approximately 99.7% of women have platelet counts between 65.2 and 431.8.

Step-by-step explanation:

The complete question is: The blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 248.5 and a standard deviation of 61.1. ​(All units are 1000 ​cells/mu​l.) using the empirical​ rule, find each approximate percentage below.

a. What is the approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 126.3 and 370.7​?

b. What is the approximate percentage of women with platelet counts between 65.2 and 431.8​?

We are given that the blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 248.5 and a standard deviation of 61.1.

Let X = the blood platelet counts of a group of women

The z-score probability distribution for the normal distribution is given by;

                             Z  =    ~ N(0,1)

where, = population mean = 248.5

            = standard deviation = 61.1

Now, the empirical rule states that;

• 68% of the data values lie within 1 standard deviation away from the mean.

• 95% of the data values lie within 2 standard deviations away from the mean.

• 99.7% of the data values lie within 3 standard deviations away from the mean.

(a) The approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 126.3 and 370.7 is given by;

As we know that;

P( < X < ) = 0.95

P(248.5 - 2(61.1) < X < 248.5 + 2(61.1)) = 0.95

P(126.3 < X < 370.7) = 0.95

Hence, approximately 95% of women with platelet counts within 2 standard deviations of the​ mean.

(b) The approximate percentage of women with platelet counts between 65.2 and 431.8​ is given by;

Firstly, we will calculate the z-scores for both the counts;

z-score for 65.2 =

                           = = -3

z-score for 431.8 =

                           = = 3

This means that approximately 99.7% of women have platelet counts between 65.2 and 431.8.

Final answer:

Using the empirical rule, approximately 68% of values fall within 1 standard deviation from the mean in a bell-shaped distribution. For ranges 2 or 3 standard deviations from the mean, the respective approximate percentages are 95% and 99.7%.

Explanation:

The question refers to the Empirical rule, which in statistics, is also known as the Three-sigma rule or the 68-95-99.7 rule. This rule is a shortcut for remembering the proportion of values in a normal distribution that are within a given distance from the mean: 68% are within 1 standard deviation, 95% are within 2 standard deviations, and 99.7% are within 3 standard deviations.

Without given specific values for the mean or standard deviations, we can discuss the problem in a general sense:

• For part a, the percentage of women with platelet counts within 1 standard deviation from the mean is approximately 68% under the Empirical rule.
• For part b, it depends on how many standard deviations from the mean the range mentioned lies. If it refers to two standard deviations from the mean, then 95% of women would fall into this range, if it refers to three standard deviations, then approximately 99.7% would be the case.

Learn more about Empirical Rule here:

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Answer:

If Connor makes x dollars in sales, he will make 0.05x + 300 that week.

He makes $408.75 in a week if he makes $2175 in sales.

Step-by-step explanation:

y = 0.05x + 300

y = 0.05(2175) + 300

y = 408.75

Answer:

Sorry this is a really really late reply but to find the median on the graph you need to find the mid value, so for example if the y axis goes up to 60, then the middle of the values will be 30. You go across this 30th value and find the median.

Hope this helps.