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The solubility of glucose at 30°C is125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water at 30°C. Explain your classification, and describe how you could increase the amount of glucose in the solution without adding more glucose.

Answers

Answer 1

Answer:

Answer:

Saturated solution

We should raise the temperature to increase the amount of glucose in the solution without adding more glucose.

Explanation:

Step 1: Calculate the mass of water

The density of water at 30°C is 0.996 g/mL. We use this data to calculate the mass corresponding to 400 mL.

$400 mL * (0.996g)/(1mL) =398g$

Step 2: Calculate the mass of glucose per 100 g of water

550 g of glucose were added to 398 g of water. Let's calculate the mass of glucose per 100 g of water.

$100gH_2O * (550gGlucose)/(398gH_2O) = 138 gGlucose$

Step 3: Classify the solution

The solubility represents the maximum amount of solute that can be dissolved per 100 g of water. Since the solubility of glucose is 125 g Glucose/100 g of water and we attempt to dissolve 138 g of Glucose/100 g of water, some of the Glucose will not be dissolved. The solution will have the maximum amount of solute possible so it would be saturated. We could increase the amount of glucose in the solution by raising the temperature to increase the solubility of glucose in water.

Answer 2

Answer:

The solution made by adding 550 g of glucose to 400 mL of water at 30°C is saturated. If you want to increase the amount of glucose in the solution without adding more glucose, you can increase the temperature.

The solution made by adding 550 g of glucose to 400 mL of water at 30°C is saturated.

Since the solubility of glucose at 30°C is 125 g/100 g water, adding 550 g of glucose to 400 mL of water exceeds the maximum amount of glucose that can dissolve in the given amount of water.

To increase the amount of glucose in the solution without adding more glucose, you can increase the temperature. Higher temperatures generally increase the solubility of solutes in water. By increasing the temperature, you can dissolve more glucose in the solution.

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Dinitrogen monoxide has a structural formula of NNO and requires resonance structures in order to draw the Lewis structures of the molecule. Based on formal charge distributions, themostsignificant (stable) resonance structure for this molecule exhibits the order of formal charges for the 1st N, the central N, and the O atoms, respectively, as:A. 0,+1,-1
B. -1,+1,0
C. -2,+3,-1
D. 0,0,0

Answers

Three resonance structures contribute to the structure of dinitrogen monoxide.

The resonance structure is invoked when a single structure can not sufficiently explain all the bonding properties of a compound. All the various contributing structures contribute to the final structure of the compound but not all to the same degree.

There are three resonance structures of dinitrogen monoxide. The most stable structure is always the structure that has the formal charges as -1, +1 and zero as shown.

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Answer:

A. 0, +1, -1

Explanation:

You can draw the lewis structure for NNO 3 ways: With two double bonds N=N=O, with a triple bond between the N and O and single bond between the two N's, or a triple bond between the two N's and a single bond between the N and O.

The goal is to have formal charges that are as small as possible, to have no identical formal charges on adjacent atoms, and to have the most negative formal charge on the most electronegative atom. The most stable structure is the one with the triple bond between the two N's because it gives the formal charges 0, 1, and -1 respectively. Unlike the other two structures, the negative formal charge is correctly placed on O, the most electronegative atom.

The osmotic pressure, π, of a solution of glucose is 132 atm . find the molarity of the solution at 298 k.

Answers

The formula for osmotic pressure is:

$\Pi = iMRT$

where $\Pi$ is osmotic pressure, $i$ is van't Hoff's factor, $M$ molarity, $R$ is Ideal gas constant, and T is Temperature.

$\Pi$ = 132 atm

The van't Hoff's factor for glucose, $i$ = 1

$R = 0.08206 Latmmol^(-1)K^(-1)$

$T = 298 K$

Substituting the values in the above equation we get,

$132 atm = 1* M* 0.08206 Latmmol^(-1)K^(-1)* 298$

$M = (132 atm)/(1* 0.08206 Latmmol^(-1)K^(-1)* 298) = 5.4797 molL^(-1) \simeq 5.48 molL^(-1)$

So, the molarity of the solution is $5.48 molL^(-1)$ .

A balloon filled with 0.500 L of air at sea level is submerged in the water to a depth that produces a pressure of 3.25 atm. What is the volume of the balloon at this depth? a. 0.154 L b. 6.50 L c. 0.615 L d. 1.63 L d. None of the above

Answers

"0.154 L" is the volume of the balloon.

Given:

Pressure,

$P_1 = 1 \ atm$
$P_2 = 3.25 \ atm$

Volume,

$V_1 = 0.5 \ L$
$V_2 = ?$

As we know,

→ $P_1. V_1 = P_2 .V_2$

or,

→ $V_2 = (P_1. V_1)/(P_1)$

By substituting the values, we get

$= (0.5* 1)/(3.25)$

$= (0.5)/(3.25)$

$= 0.154 \ L$

Thus the above answer i.e., "option a" is correct.

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Answer:

Option a . 0.154L

Explanation:

P₁ . V₁ = P₂ . V₂

when we have constant temperature and constant moles for a certain gas.

At sea level, pressure is 1 atm so:

0.5 L . 1atm = V₂ . 3.25 atm

(0.5L . 1atm) / 3.25 atm = 0.154 L

The number-average molecular weight of a polypropylene is 663419 g/mol. Compute the degree of polymerization (Key in your answer as the whole number only. Avoiding round-off error by using all the numbers during intermediate steps.

Answers

Answer:

15766

Explanation:

The average molecular weight of the polypropylene = 663419 g/mol.

The mass of the repeating unit , monomer which is propylene = 42.08 g/mol

The degree of polymerization is:

$DP_n=\frac {Total\ molecular\ weight\ of\ the\ polymer}{Molecular\ weight\ of\ the\ monomer}$

$DP_n=\frac {663419\ g/mol}{42.08\ g/mol}$

Degree of polymerization = 15766

Explain why HCl can be a strong electrolyte, but a dilute HCl solution can be a poor conductor?

Answers

Answer:

Because as the concentration is diminished, the capacity to transfer electricity is diminished as well.

Explanation:

Hello!

In this case, since electrolytes are substances that are able to conduct the electricity in aqueous media (solutions in which water is the the solvent) because they have the capacity to form ions with both positive and negative charges, due to the fact that HCl is a strong acid, we notice it is fully ionized in solution and therefore it is a strong electrolyte. However, when the concentration is diminished, we can notice that strength is diminished as well because less ions will have the capacity to transfer the electricity and therefore it'd become a poor conductor or weak electrolyte.

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6 CO2 + 6 H2O
How many atoms of each element are in
the equation?

Answers

Answer:

There are 6 Carbon dioxides, and 6 waters, but there are 6 carbons, 18 oxygens, and 12 hydrogens.

Explanation:

Answer:

6 carbon atoms

18 oxygen atoms

12 hydrogen atoms

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