The leg of a right triangle is 3 units and the hypotenuse is 4 units. What is the length, in units, of the other leg of the triangle?square root of 5
square root of 7

5

7

Answers

Answer 1
Answer:

Answer:

square root of 7

Step-by-step explanation:

Each right angle triangle has 3 sides known as the opposite, adjacent and hypotenuse sides. The relationship between these 3 sides is as defined by pythagoras theorem which states that

a² + b² = c²

where a and b are the lengths of the opposite and adjacent sides (in no particular order) and c is the length of the hypotenuse side.

Given that the leg of a right triangle is 3 units and the hypotenuse is 4 units, it means that

a² + 3² = 4

where a is the length in units, of the other leg of the triangle

a² = 4² - 3

a² = 16 - 9

= 7

a = √7


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What are the first four terms in the multiplication, or geometric, pattern in which the first term is 7 and then each term is multiplied by 4?7, 28, 112, 4487, 28, 56, 1127, 11, 15, 1928, 112, 448, 1792

Select the equivalent expression

Answers

to my calculations i think it’s c

a model rocket is launched into the air from ground level. the height, in feet, in feet, is modeled by p(x)=16x^2+32x, where x is the number of elapsed seconds. what is the total number of seconds the model rocket will be in the air?

Answers

Since you are given the function for the height of a rocket, we are to look for the value of X that gives us a value of p(x) = 0, which means that the model rocket has landed back onto the ground. One easy way to do this is by table method, meaning we substitute values of x to see if we can obtain the needed value of P(x). We should start from 1, since using 0 as our first value means that the rocket has not even launched up yet. Let us do this below:

x | p(x) = -16x^2+32x
--------------------------
1 | p(1) = -16(1)^2 + 32(1) = 16
2 | p(2) = -16(2)^2 + 32(2) = 0

Having obtained the desired result at x = 2, this means that the model rocket has been in the air for 2 seconds.

Final answer:

The model rocket is in the air for 0 seconds according to the given equation, which implies an immediate impact upon launch.

Explanation:

In this mathematical scenario, the model rocket's height p(x) over time x (elapsed seconds) is given by the quadratic equation p(x) = 16x^2 + 32x. The total amount of time the rocket is in the air will be the point when the rocket returns to ground level. This occurs when p(x) = 0, which represents the rocket's height being zero feet above the ground.

We can find out when this occurs by solving the quadratic equation for x. We can rearrange the quadratic equation to 16x^2 + 32x = 0. Factoring out 16x gives us 16x(x + 2) = 0. Solving for x will give two potential solutions: x = 0 (the initial launch point) and x = -2. However, since time cannot be negative in this context, we discard the -2 and our answer is x=0 s, the total time the model rocket will be in the air after being launched is 0 seconds.

Learn more about Quadratic Equations here:

brainly.com/question/30098550

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Pete earns $8.50 per hour plus tips. On Tuesday, he received $16 in tips.How many hours did Pete work if he earned a total of $50 on Tuesday?


Help me plz

Answers

Answer:

Pete worked for 4 hours.

Step-by-step explanation:

If you subtract his tips from his overall total (50-16) you get 34. Now you divide what's left of his total by his hourly wage (34/8.5) which gets you 4.

How much times can 2 go into 125

Answers

Solve:-

125 ÷ 2 = 62.5
2 × 62 = 124
2 goes in 125, 62 times with 1 left over.

Newton's second law says force (f) is equal to mass (m) times acceration (a). A scientist wants to calculate the force of an object where the acceleration of gravity (g) is 9.8 m/s2. Use the function to calculate the force for an object with a mass (m) of 0.29 kilograms.

Answers

Force = mass x accerelation
= 0.29 x 9.8
= 2.842 N

Answer:

2.842 N


Step-by-step explanation:

Newton's second law is given by the equation  F=ma

Where,

  • F is the force in Newtons
  • m is the mass in kilograms (kg)
  • a is acceleration given in meters per second squared

Given in the problem,

m = 0.29 kg, and

a = 9.8 meters per second squared


Substituting into the formula gives us F:

F=ma\nF=(0.29)(9.8)\nF=2.842  Newtons (N)

16. Expand (2x - 1)(x - 3).
A. 2x2 - 7X+3 B. 2x2 +7x+3
C. 2x2-7X-3 D. 2x2+7X-3 E. x2+7X-3​

Answers

Answer:

Hey there!

(2x-1)(x-3)

2x^2-1x-6x+3

2x^2-7x+3

Hope this helps :)

Answer:

see below

Step-by-step explanation:

the simple answer is a if you need an explanation just comment