Four students were discussing how to find the unit rate for a proportional relationship. Which method is valid?V
"Look at the graph of the relationship. Find the y-value of the point that corresponds to x = 1. That value is the
"Look at the graph of the relationship. Count the number of units up and the number of units to the right onen
arrive at the next point on the graph. Write these two numbers as a fraction."
"Look at the graph of the relationship. Find the x-value of the point that corresponds to y = 2. That value is the
"Look at the graph of the relationship. Find two points which have y-values that are one unit apart. The unit ra
difference in the corresponding x-values."
0 M2

Answers

Answer 1

Answer:

Answer:

Look at the graph of the relationship. Find the y-value of the point that corresponds to x = 1. That value is the unit rate.

Step-by-step explanation:

The unit rate is the change in y for a 1-unit change in x. Since the graph of a proportion will go through the origin, it is appropriate to look at the y-value for x = 1 (one unit from the origin).

___

The ratio of units up to units to the right is also the unit rate when the fraction is reduced to lowest terms. It is a "unit" rate when the denominator of the fraction is 1 unit.

Answer 2

Answer:

Step-by-step explanation:

Related Questions

The equation for 3x-10=2(x+6)
Graph the following figure in the coordinX(0,1), Y(4, - 2), Z(-5,-2)The perimeter is
Compare 2/6 and 5/8 using benchmark number. Which number can you use to compare these fraction
What’s the value of x in this problem?
A 30-ft. ladder makes an angle of 60 degrees with the horizontal when it reaches a given spot on a wall. What angle will a 35-ft. ladder make the horizontal if it reaches the sample spot?

(Algebra II) Solve the equation or formula for the indicated variable. a = 4b5h, for h

Could you explain the process to solve this type of problem? I have ten to do and this is only #1. I need to be able to solve it on my own before I continue with my lesson.

Answers

Divide by A and b5 to both sides. You can rule out option A and B. You're dividing both sides by 4b5 to isolate h by itself. Remember that when you didivde by same term aa=1 you get ONE. so h is alone. The answer is D.

According to a past survey, 23% of Americans have hypertension. After a stringent regimen of diet and exercise, 75 people were then tested and 18 were found to have hypertension. Based on this sample, does diet and exercise reduce hypertension? Use a significance level of 0.05.a) yesb) no

Answers

Answer:No, Diet and exercise does not reduce hypertension.

Step-by-step explanation:

Since we have given that

p = 0.23

n = 75

x = 18

So, $\hat{p}=(x)/(n)=(18)/(75)=0.24$

So, hypothesis would be

$H_0:p=\hat{p}\n\nH_a:\hat{p}<p$

So, the test statistic value would be

$z=\frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}\n\nz=\frac{0.24-0.23}{\sqrt{(0.23* 0.77)/(75)}}\n\nz=(0.01)/(0.049)\n\nz=0.204$

At α = 0.05 level of significance, we get

critical value = 1.96

and 1.96>0.204.

so, we will accept the null hypothesis.

Hence, No, Diet and exercise does not reduce hypertension.

Help me please!!!!!!!!!!!!!

Answers

Step-by-step explanation:

0 < X < 24

.....................

A rental company rents big-screen televisions for $22 down plus $4 a day. If the final bill is $46, how many days did you rent the television for? *

Answers

Answer: 6 days

Step-by-step explanation:

take 22 off of the final price 46-22=24

now divid 24 by 4

and u have 6

The rate of change of the temperature T(t) of a body is still governed bydT
/dt
= âk(T â A), T(0) = T0,

when the ambient temperature A(t) varies with time. Suppose the body is known to have

k = 0.2

and initially is at 32Â°C; suppose also that

A(t) = 20eât.

Find the temperature T(t).

Answers

Answer:

$T(t)=5e^(-t)+27e^(-0.2t)$

Step-by-step explanation:

QUESTION

The rate of change of the temperature T(t) of a body is still governed by

$(dT)/(dt)=-k(T-A), T(0)=T_0$ when the ambient temperature A(t) varies with time. Suppose the body is known to have k = 0.2 and initially is at 32°C; suppose also that $A(t) = 20e^(-t)$ . Find the temperature T(t).

SOLUTION

$(dT)/(dt)=-k(T-A), T(0)=T_0, A(t) = 20e^(-t), k=0.2$

$(dT)/(dt)=-0.2T+20(0.2)e^(-t)\n(dT)/(dt)+0.2T=4e^(-t)\n\text{Integrating factor}=e^(0.2t)\n(dTe^(0.2t))/(dt)=4e^(-t)e^(0.2t)\ndTe^(0.2t)=4e^(-t)e^(0.2t)dt\n\int d[Te^(0.2t)]=4\int e^(-t(1-0.2))dt\nTe^(0.2t)=4\int e^(-0.8t)dt\nTe^(0.2t)=(4)/(-0.8) e^(-0.8t)+C, \text{C a constant of integration}\nTe^(0.2t)=-5 e^(-0.8t)+C\nT(t)=5 e^(-0.8t)e^(-0.2t)+Ce^(-0.2t)\nT(t)=5e^(-t)+Ce^(-0.2t)\nWhen t=0, T_0=32\n32=5+C\nC=27$

Therefore:

$T(t)=5e^(-t)+27e^(-0.2t)$

(Ill give brainliest :) )Which equations have a value less than 6,766?

A. one fourth x 6,766 = ________

B. 6 x 6,766 = ________

C. one half x 6,766 = ________

D. 1 x 6,766 = ________

1) A and C
2) D and B
3) A and B
4) C and D

Answers

Answer:

A and C

Step-by-step explanation:

A.¼×6766=1691.5

B.6×6766=40,596

C.½×6766=3383

D.1×6766=6766

Other Questions

use the exact value of cos 11pi/6 and the half-angle identity for sine to find the exact value of sin 11pi/12

An algebraic relationship of that quantity is greater than or less then another quantity ?

What are 3 careers where similarity is used

The fraction 24/28 In simplest form is____.12/1448/566/96/7