Energy is the capacity to do work, but not to produce heat

Answers

Answer 1

Answer: Energy and Work Energy is the capacity to do work or to produce heat. Internal energy is the sum of kinetic energy and the potential energy. ... The KE would increase because heating something causes an increase in temperature.

Answer 2

Answer:

Final answer:

Energy is the capacity to do work but not to produce heat. In physics, energy can exist in various forms, including mechanical and thermal energy.

Explanation:

Energy is the capacity to do work and is an important concept in physics. In the context of this question, it is stated that energy is the capacity to do work but not to produce heat. This highlights the distinction between the two forms of energy. For example, mechanical energy can be used to perform work on an object and cause it to move, while thermal energy is associated with heat and not directly related to work. However, it's important to note that energy can be converted from one form to another, such as converting mechanical energy to thermal energy in a friction process.

Learn more about Energy here:

brainly.com/question/36891624

#SPJ6

Related Questions

A sheet of aluminum alloy is cold-rolled 33 percent to a thickness of 0.096 in. If the sheet is then cold-rolled to a final thickness of 0.061 in., what is the total percent cold work done
A crate of eggs is located in the middle of the flatbed of a pickup truck as the truck negotiates a curve in the flat road. The curve may be regarded as an arc of a circle of radius 35.0 m. If the coefficient of static friction between crate and truck is 0.600, how fast can the truck be moving without the crate sliding?
Hello I would like to know if there is a course or a book in which to learn quantum mechanics is easier, I am currently studying quantum mechanics, but it is a little complicated because I have some mathematical doubts, but nevertheless I would like to know if there is a course or book that explains and develops the problems so that they are understandable. and if there is no book or course I would appreciate an honest and complete answer, thank you very much and greetings.Sorry I know that this is not a problem but what better to ask the experts do not believe.
Water, initially saturated vapor at 4 bar, fills a closed, rigid container. The water is heated until its temperature is 360°C. For the water, determine the heat transfer, in kJ per kg of water. Kinetic and potential energy effects can be ignored.
A space vehicle of mass m has a speed v. At some instant, it separates into two pieces, each of mass 0.5m. One of the pieces is at rest just after the separation. How much work was done by the internal forces that caused the separation

At takeoff, a commercial jet has a speed of 72 m/s. Its tires have a diameter of 0.89 m. Part (a) At how many rev/min are the tires rotating? Part (b) What is the centripetal acceleration at the edge of the tire in m/s^2?

Answers

Answer:

a) Revolutions per minute = 2.33

b) Centripetal acceleration = 11649.44 m/s²

Explanation:

a) Angular velocity is the ratio of linear velocity and radius.

Here linear velocity = 72 m/s

Radius, r = 0.89 x 0. 5 = 0.445 m

Angular velocity

$\omega =(72)/(0.445)=161.8rad/s$

Frequency

$f=(2\pi)/(\omega)=(2* \pi)/(161.8)=0.0388rev/s=2.33rev/min$

Revolutions per minute = 2.33

b) Centripetal acceleration

$a=(v^2)/(r)$

Here linear velocity = 72 m/s

Radius, r = 0.445 m

Substituting

$a=(72^2)/(0.445)=11649.44m/s^2$

Centripetal acceleration = 11649.44m/s²

A 2-C charge experiences a force of 40 N when put at a certain location inspace. The electric field at that location is a. 2 N/C.b. 20 N/C. c. 30 N/C. d.
40 N/C. e. 60 N/C.

Answers

Answer:

E = 20 N/C

Explanation:

Given that,

Charge, q = 2 C

Force experience, F = 40 N

We need to find the electric field at that location.

The electric field in terms of electric force is given by :

F = qE

Where

E is the electric field

$E=(F)/(q)\n\nE=(40\ N)/(2\ C)\nE=20\ N/C$

So, the electric field at that location is 20 N/C.

A single-turn circular loop of wire of radius 5.0 cm lies in a plane perpendicular to a spatially uniform magnetic field. During a 0.02500.0250-\text{s}s time interval, the magnitude of the field increases uniformly from 200 to 300 mT. Determine the magnitude of the emf induced in the loop

Answers

Given Information:

time = Δt = 0.0250 seconds

Radius = r = 5 cm = 0.05 m

Change in Magnetic field = ΔB = (0.300 - 0.200) T

Number of turns = N = 1

Required Information:

Magnitude of induced emf = ξ = ?

Answer:

Magnitude of induced emf = ξ = 3.141x10⁻² V

Explanation:

The EMF induced in a circular loop of wire in a changing magnetic field is given by

ξ = -NΔΦ/Δt

Where change in flux ΔΦ is given by

ΔΦ = ΔBA

ΔΦ = ΔBπr²

ΔΦ = (0.300 - 0.200)*π*(0.05)²

ΔΦ = 7.854x10⁻⁴ T.m²

ξ = -NΔΦ/Δt

ξ = -(1*7.854x10⁻⁴)/0.0250

ξ = -3.141x10⁻² V

The negative sign is due to Lenz law.

Answer:

-0.0314 V

Explanation:

Parameters given:

Initial magnetic field, Bini = 200 mT = 0.2T

Final magnetic field, Bfin = 300mT = 0.3 T

Number of turns, N = 1

Radius, r = 5 cm = 0.05 m

Time, t = 0.025 secs

Induced EMF is given as:

EMF = [-(Bfin - Bini) * N * pi * r²] / t

EMF = [-(0.3 - 0.2) * 1 * 3.142 * 0.05²] / 0.025

EMF = (-0.1 * 3.142 * 0.0025) / 0.025

EMF = -0.0314 V

What power lens is needed to correct for farsightednesswherethe uncorrrected near point is 75 cm?

Answers

To solve this problem we will apply the concept related to the lens power with which farsightedness can be corrected. Mathematically this value is given by the relationship,

$P = (1)/(f)$

Here,

f =focal length

In turn, said expression can be exposed in terms of the distance of the object and the image as:

$P = (1)/(p)+(1)/(q)$

Here,

p = Object Distance ( By convention is 25cm)

q = Image distance

Replacing we have,

$P = (1)/(0.25)+(1)/(-0.75)$

$P = +2.67D$

Therefore the power lens that is needed to correct for farsightedness is +2.67D

Planets A and B have the same size, but planet A is half the mass of planet B.Which statement correctly explains the weight you would experience on each
planet?
A. You would weigh the same on both planets because the planets
are the same size.
B. You would weigh less on planet A because it has less mass than
planet B.
C. You would weigh the same on both planets because your mass
would be the same on both.
D. You would weigh more on planet A because it has less mass than
planet B.

Answers

The statement which correctly explains the weight you would experience on each planet is: B. You would weigh less on planet A because it has less mass than planet B.

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, the weight of an object is given by the formula;

$Weight = mg$