PHYSICS MIDDLE SCHOOL

A child drags a 0.398 kg toy dogacross flat ground at constant speed,
with a 4.63 N force at a 63.0° angle.
What is the force of friction on the
toy?
(Hint: You do NOT need to know the
coefficient of friction.)

Answers

Answer 1
Answer:

The force of friction on the toy is 2.10 N and it acts opposite to the direction of its motion.

What is friction?

A force called friction prevents one solid object from rolling or sliding over another. Although frictional forces, such the traction required to walk without slipping, may be advantageous, they can provide a significant amount of resistance to motion.

Given parameters:

mass of the toy dog: M = 0.398 kg.

Applied force: F = 4.63 N.

Angle of application of force: θ = 63.0°

Hence, horizontal component of applied force = F cosθ

= 4.63 × cos63.0° N

= 2.10 N.

As the child drags a 0.398 kg toy dog across flat ground at constant speed, this component of applied force is nullified by force of friction.

Hence,  the force of friction on the toy is 2.10 N and it acts opposite to the direction of its motion.

Learn more about friction here:

brainly.com/question/13000653

#SPJ2
Answer 2
Answer:

Answer:

-2.1 N

Explanation:

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