Help this is my last grade of the year and I need to do good

Answers

Answer 1

Answer:

Answer:

The volume is 58.64.

I hope this helps you out :)

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Two rectangles are similar. One has a length of 14 cm and a width of 9 cm, and the other has a width of 3 cm. Find the length of the second rectangle. Round to the nearest tenth if necessary.A. 4.7 cm B. 1.9 cm C. 5.4 cm D. 3.5 cm

Solve for w k=2b-5w/3k

Answers

Answer:

b = $(2b - 3k^(2) )/(5)$

Step-by-step explanation:

To solve for w in this equation;

k = $(2b - 5w)/(3k)$

This implies we have to make w the subject of the formula.

To make w subject of the formula, first we cross multiply.

3k × k = 2b - 5w

3k² = 2b -5w

Now we will subtract 2b from both- side of the equation

3k² - 2b = -5w

we want to make the right hand side of the equation positive, to do that , we will just multiply through by minus sign. The equation becomes;

-3k² + 2b = 5w

We can rearrange the equation;

2b - 3k² = 5w

5w = 2b - 3k²

Then we will now divide both-side of the equation by 5

$(5w)/(5) = (2b - 3k^(2) )/(5)$

In the left side of the equation, the 5 at the numerator will cancel out the 5 at the denominator.

Hence;

w = $(2b - 3k^(2) )/(5)$

$k = (2b - 5w)/(3k)$
$3k^(2) = 2b - 5w$
$3k^(2) + 5w = 2b$
$5w = 2b - 3k^(2)$
$w = (2)/(5)b - (3)/(5)k^(2)$

How do i solve this problem 4s -12 = -5s + 51

Answers

$4s-12=-5s+51\ \ \ \ /+12\n\n4s-12+12=-5s+51+12\n\n4s=-5s+63\ \ \ /+5s\n\n4s+5s=-5s+5s+63\n\n9s=63\ \ \ /:9\n\n9s:9=63:9\n\ns=7$

4s-12=-5s+51
+12= +12
4s=-5s+63
+5s =+5s
9s=63
9/9=63/9
s=7

The perfect squares between 20 and 61

Answers

by-step explanation:

8) A crew is made up of 8 men; the rest are women. 66% of the crew are men. How many people are in the crew?

Answers

☁️ Answer ☁️

12.

(66 2/3)

---------- (x) = 8

100

Solve for x

(66 2/3)x = 800

x = 800/(66 2/3)

x = 800/(200/3)

x = 800(3/200)

x = 4(3)

x = 12

Here's the link: https://www.wyzant.com/resources/answers/286307/a_crew_is_made_up_of_8_men_the_rest_are_women_66_2_3_are_men_how_many_people_are_in_the_crew

Hope it helps.

Have a nice day noona/hyung.

Answer:

12 crew members I think hope this helps :)

Step-by-step explanation:

The area of a rectangular room is 750 square feet. the width of the room is 5 feet less than the length of the room. which equations can be used to solve for y, the length of the room?

Answers

Answer:

Width=25 ft and length=30 ft

Step-by-step explanation:

In order to find the answer let's remember that the area (A) of a rectangle is:

$A=width*length$

Let's assume that the length of the room is 'X' feet.

Becuase the problem mentioned that the width (Y) of the room is 5 feet less than the length, then:

$Y=X-5$

Now, using the area equation we have:

A=width*length

$750=X*Y$ but using the width expression we have:

$750=X*(X-5)$

$0=X^2-5X-750$

Using the root's equation we have:

$X=\frac{-b\±\sqrt{b^(2)-4ac}}{2a}$

$X=\frac{-(-5)\±\sqrt{(-5)^(2)-(4*1*(-750)}}{2*1}$

$X1=30$

$X1=-25$

Because the length (X) can't be negative, then length=30 feet. In order to find the width we have:

$Y=X-5$

$Y=30-5$

$Y=25$

So the width is 25 feet.

In conclusion the room has a width=25 ft and length=30 ft.

I hope this helps you

The graph of which function has an axis of symmetry at x =-1/4 ?f(x) = 2x2 + x – 1

f(x) = 2x2 – x + 1

f(x) = x2 + 2x – 1

f(x) = x2 – 2x + 1

Answers

we know that

The equation of the vertical parabola in vertex form is equal to

$y=a(x-h)^(2)+k$

where

(h,k) is the vertex

The axis of symmetry is equal to the x-coordinate of the vertex

$x=h$ ------> axis of symmetry of a vertical parabola

we will determine in each case the axis of symmetry to determine the solution

case A) $f(x)=2x^(2)+x-1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+1=2x^(2)+x$

Factor the leading coefficient

$f(x)+1=2(x^(2)+0.5x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+1+0.125=2(x^(2)+0.5x+0.0625)$

$f(x)+1.125=2(x^(2)+0.5x+0.0625)$

Rewrite as perfect squares

$f(x)+1.125=2(x+0.25)^(2)$

$f(x)=2(x+0.25)^(2)-1.125$

the vertex is the point $(-0.25,-1.125)$

the axis of symmetry is

$x=-0.25=-(1)/(4)$

therefore

the function $f(x)=2x^(2)+x-1$ has an axis of symmetry at $x=-(1)/(4)$

case B) $f(x)=2x^(2)-x+1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-1=2x^(2)-x$

Factor the leading coefficient

$f(x)-1=2(x^(2)-0.5x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-1+0.125=2(x^(2)-0.5x+0.0625)$

$f(x)-0.875=2(x^(2)-0.5x+0.0625)$

Rewrite as perfect squares

$f(x)-0.875=2(x-0.25)^(2)$

$f(x)=2(x-0.25)^(2)+0.875$

the vertex is the point $(0.25,0.875)$

the axis of symmetry is

$x=0.25=(1)/(4)$

therefore

the function $f(x)=2x^(2)-x+1$ does not have a symmetry axis in $x=-(1)/(4)$

case C) $f(x)=x^(2)+2x-1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+1=x^(2)+2x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+1+1=x^(2)+2x+1$

$f(x)+2=x^(2)+2x+1$

Rewrite as perfect squares

$f(x)+2=(x+1)^(2)$

$f(x)=(x+1)^(2)-2$

the vertex is the point $(-1,-2)$

the axis of symmetry is

$x=-1$

therefore

the function $f(x)=x^(2)+2x-1$ does not have a symmetry axis in $x=-(1)/(4)$

case D) $f(x)=x^(2)-2x+1$

Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-1=x^(2)-2x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-1+1=x^(2)-2x+1$

$f(x)=x^(2)-2x+1$

Rewrite as perfect squares

$f(x)=(x-1)^(2)$

the vertex is the point $(1,0)$

the axis of symmetry is

$x=1$

therefore

the function $f(x)=x^(2)-2x+1$ does not have a symmetry axis in $x=-(1)/(4)$

the answer is

$f(x)=2x^(2)+x-1$

axis of symmetry is the x value of the vertex

for
y=ax^2+bx+c
x value of vertex=-b/2a

first one
-1/2(2)=-1/4
wow, that is right

answer is first one
f(x)=2x^2+x-1