What is the measure of angle x?A pair of parallel lines is cut by a transversal. An exterior angle on the left of the transversal is labeled as 45 degrees. An interior angle on the right of the transversal, which is not vertically opposite to the 45 degree angle, is labeled as x.

45 degrees
90 degrees
135 degrees
140 degrees
1SinnamonBun avatar

Answers

Answer 1
Answer: The correct angle for x is 135 degrees.
Answer 2
Answer:

Answer:

Definitely 135



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What is the relationship between the 6s in 660,472

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Marie buys 4 cans of orange drinks $32. Atty buys 2 cans of orange drinks $18.By using the matrix method, state the price for each cans of the drink.

Answers

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Zulfiya earns her regular pay $7.50 per hour for up to 40 hours of work in a week. For each hour over 40 hours of work in a week, Zulfiya is paid 1.5 times her regular pay. How much does Zulfiya earn for a week in which she works 46 hours? The answer is $367.5

Please show me the way of your solution

Answers

Zulfiya get $7.5 for each hour.
If she works more than 40 hrs she gets 1.5 times her regular pay.
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For next six hrs she gets 1.5 times her pay i.e. 7.5×1.5=11.25 for one hr.
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A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = –16t2 + 48t + 190.What is the maximum height of the projectile?
A. 82 feet
B. 190 feet
C. 226 feet
D. 250 feet

Answers

Answer:

Option c is correct

226 feet  is the maximum height of the projectile.

Step-by-step explanation:

A quadratic equation y=ax^2+bx+c,   ....[1]

then the axis of symmetry is given by:

x = -(b)/(2a)

As per the statement:

The path of the projectile is modeled using the equation :

h(t) = -16t^2+48t+190            ....[2]

where, h(t) is the height after t time.

On comparing with [1] we have;

a = -16 and b = 48

then;

t = -(48)/(2(-16)) = (48)/(32) = 1.5 sec

Substitute this in [2]  we have;

h(1.5) = -16(1.5)^2+48(1.5)+190  

h(1.5) = -36+72+190  

Simplify:

h(1.5) = 226 ft

Therefore, the maximum height of the projectile at 1.5 sec is, 226 feet.

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Answers

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