MATHEMATICS MIDDLE SCHOOL

Write an equation of the line that passes through a pair of points:(-2,-2), (5,-5)
A. Y=3/7x - 20/7
B. Y=-3/7x + 20/7
C. Y= -3/7x + 7/20
D. Y= -3/7x - 7/20

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

(-2,-2) , (5,-5)

$Slope=(y_(2)-y_(1))/(x_(2)-x_(1))\n\n=(-5-(-2))/(5-(-2))\n\n=(-5+2)/(5+2)\n\n=(-3)/(7)\n$

(-2,-2), m= -3/7

Line equation: y -y1 =m*(x -x1)

y-(-2) = -(-3/7)(x - [-2])

$y+2=(-3)/(7)*(x+2)\n\ny+2=(-3)/(7)*x+((-3)/(7))*2\n\ny+2=(-3)/(7)x-(6)/(7)\n\ny=(-3)/(7)x-(6)/(7)-2\n\ny=(-3)/(7)x-(6)/(7)-(2*7)/(1*7)\n\ny=(-3)/(7)x-(6)/(7)-(14)/(7)\n\ny=(-3)/(7)x-(20)/(7)$

Answer 2

Answer:

y = -(3/7)x - 20/7

Step-by-step explanation:

Slope: (-5 - -2)/(5 - -2)

= -3/7

y = (-3/7)x + c

-2 = (-3/7)(-2) + c

-2 - 6/7 = c

c = -20/7

y = -(3/7)x - 20/7

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Lets solve this step by step.A is not a positive because (-9)*8=-72.B if positive because -12*(-3)=36. A negative times a negative is a positive.C is also a positive because (-2/5)*(-4) is a positive.D is not a positive because like A, one is negative and the other number is positive. A negative times a positive is a negative.I hope it helped!

We need to solve this by looking at each answer choice.

A. $- (w)/(9)=8$

To solve for w, we need to multiply by -9 on both sides.

So, $-(w)/(9) * -9 = 8 * -9\n\nw = -72$

This is not a positive solution. So eliminate A.

B. $(-12) = (y)/((-3))$

To solve for y, we need to multiply by -3 on both sides.

So, $(-12) * (-3) = (y)/((-3)) * (-3)\n\ny = 36$

This is a positive solution. This is one of our answers.

C. $[tex]-4* (-5)/(2)= -(2)/(5)z* -(5)/(2)\n\nz = 10$ [/tex]

We need to multiply by -5/2 on both sides to solve for z.

This is a positive solution. This is one of our answers.

D. $(1)/(7)x = -2$

We need to multiply by 7 on both sides to solve for x.

So, $(1)/(7) x * 7 = -2 * 7\n\nx = -14$

This is a negative solution. So this is not the answer.

So your final answer is B and C.

Select ALL of the expressions that are equivalent to
$16 (5)/(2)$

Answers

Answer:

A, B, C

Step-by-step explanation:

$a^(m)/(n)=\sqrt[n]{a^m}\n\n(a^n)^m=a^(nm)\n\na^n\cdot a^m=a^(n+m)\n\n========================$

$16^(5)/(2)=\sqrt[2]{16^5}=√(16^5)\to\boxed{B}\n\n16=4^2\to16^(5)/(2)=\left(4^2\right)^(5)/(2)=4^{2\cdot(5)/(2)}=4^5\to\boxed{A}\n\n16^(5)/(2)=16^{2(1)/(2)}=16^{2+(1)/(2)}=16^2\cdot16^(1)/(2)=\left(16^2\right)\left(16^(1)/(2)\right)\to\boxed{C}$