What is the solubility of substance?

Answers

Answer 1

Answer:

Explanation:

Solubility is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. The resulting solution is called a saturated solution.

Related Questions

200.0 grams of an organic compounds known to contain 98.061 grams of carbon, 10.381 grams of hydrogen, 32.956 grams of oxygen and the rest is nitrogen. what is the empirical formula of the compound? what is the molecular formula of the compound if its molar mass is 194.101?
A compound has a molecular formular of C12H24O6.What is the compound's empirical formula
Use molecular orbital theory to determine whether f22+ is paramagnetic or diamagnetic.
What is the change in electrons for nitrogen in the following reaction?S + NO3 - -> SO2 + NOA. Gain 2 electronsB. Gain 3 electronsC. Lose 2 electronsD. Lose 3 electrons
1‑propanol ( nn ‑propanol) and 2‑propanol (isopropanol) form ideal solutions in all proportions. Calculate the partial pressure and the mole fraction ( yy ) of the vapor phase of each component in equilibrium with each of the given solutions at 25 °C. P∘prop=20.9 TorrPprop°=20.9 Torr and P∘iso=45.2 TorrPiso°=45.2 Torr at 25 °C. A solution with a mole fraction of xprop=0.243xprop=0.243 .

A eraser has a mass of 4g and a volume of 2cm3 what is it’s density

Answers

Answer:

The answer is 2.0 g/cm³

Explanation:

The density of a substance can be found by using the formula

$density = (mass)/(volume) \n$

From the question

mass = 4 g

volume = 2 cm³

We have

$density = (4)/(2) \n$

We have the final answer as

2.0 g/cm³

Hope this helps you

Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 50.0L tank with 14. mol of sulfur dioxide gas and 2.6 mol of oxygen gas, and when the mixture has come to equilibrium measures the amount of sulfur trioxide gas to be 1.6 mol. Calculate the concentration equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.

Answers

Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

$2SO_2 + O_2 \to 2SO_3$

The I.C.E table can be represented as:

2SO₂ O₂ 2SO₃

Initial: 14 2.6 0

Change: -2x -x +2x

Equilibrium: 14 - 2x 2.6 - x 2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction $2SO_2 + O_2 \to 2SO_3$ = 0.8325;

If we want to find:

$SO_2 + (1)/(2)O_2 \to SO_3$

Then:

$K_c = (0.8325)^(1/2)$

$\mathbf{K_c = 0.912}$

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

Which is more water soluble hexanoic acid or sodium hexanoate?

Answers

Answer:

Explanation:

Hexanoic acid [CH 3(CH 2) 4COOH] is barely soluble in water (about 1.0 g/100 g of water). Palmitic acid [CH 3(CH 2) 14COOH], with its large nonpolar hydrocarbon component, is essentially insoluble in water. The carboxylic acids generally are soluble in such organic solvents as ethanol, toluene, and diethyl ether.

hope this help ya~

I need help!! ASAP please..

Answers

Answer:

164 g

Explanation:

Hydrazine, N2H4, is a weak base and is used as fuel in the space shuttle.N2H4(aq)+H2O(l)âN2H5+(aq)+OHâ(aq)

Part A

If the pH of a 0.133 M solution is 10.66, what is the ionization constant of the base?

Express your answer using two significant figures.

Answers

Answer:

Kb = 1.6*10^-6

Explanation:

The given reaction is:

$N2H4(aq)+H2O(l)\rightarrow N2H5+(aq)+OH-(aq)$

The ionization constant of the base Kb is given as:

$Kb = ([N2H5+][OH-])/([N2H4])------(1)$

The pH = 10.66

therefore, pOH = 14-pH = 14-10.66 =3.34

$[OH-] = 10^(-pOH) =10^(-3.34) =4.57*10^(-4) M$

[N2H5+] = [OH-] = 4.57*10^-4M

[N2H4] = 0.133 M

Based on eq(1)

$Kb = ([4.57*10^(-4)]^(2))/([0.133])=1.6*10^(-6)$

The rate constant of the elementary reaction CH3OCH3(g) CH4(g) +CH2O(g) is k = 8.33×10-6 s-1 at 427°C, and the reaction has an activation energy of 245 kJ mol-1. (a) Compute the rate constant of the reaction at a temperature of 545°C. s-1 (b) At a temperature of 427°C, 8.32×104 s is required for half of the CH3OCH3 originally present to be consumed. How long will it take to consume half of the reactant if an identical experiment is performed at 545°C?

Answers

Answer:

(a) The rate constant is 3.61×10^-3 s^-1

(b) 7.12×10^4 s

Explanation:

(a) Log (K2/K1) = Ea/2.303R × [1/T1 - 1/T2]

K1 = 8.33×10^-6 s^-1

Ea = 245 kJ = 245,000 J

R = 8.314 J/mol.K

T1 = 427°C = 427+273 = 700 K

T2 = 545°C = 546+273 = 818 K

Log (K2/8.33×10^-6) = 245,000/2.303 × [1/700 - 1/818]

Log (K2/8.33×10^-6) = 2.637

K2/8.33×10^-6 = 10^2.637

K2 = 8.33×10^-6 × 433.51 = 3.61×10^-3 s^-1

(b) The relationship between temperature and the time required for reactants to be consumed is inverse

t2 = T1t1/T2

T1 = 427 °C = 700 K

t1 = 8.32×10^4 s

T2 = 545 °C = 818 K

t2 = 700×8.32×10^4/818 = 7.12×10^4 s

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