MATHEMATICS MIDDLE SCHOOL

What is the value of the expression 9 + (fraction 1 over 2)4 ⋅ 48?12
15
17
18

Answers

Answer 1
Answer:

Answer -> (12) I'm very late haha but hopes this helps!

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Need help on question 9

What is the area of this rectangle in square yards?

Answers

In the comment of the other answer, you said that the rectangle is 24 x 18 ft.

First, we have to find out how many square feet that is, and then we can convert it to square yards.

The area of a rectangle is the length multiplied by the width.

A = l x w
A = 24 x 18
A = 432 square feet

To find out how many square yards that is, we divide it by 3, because 1 yard is 3 feet.

432 ÷ 3 = 144

The area of a 24x18ft rectangle is 144 square yards.

How many grams does a 5 lb 1 oz roast weigh?

Answers

1 pound = 16 ounces

1 ounce = 28.3495 grams.


Multiply total pounds by 16 to find total ounces:


5 pounds x 16 = 80

80 + 1 = 81 total ounces.

Multiply total ounces by 28.3495 for total grams:

81 x 28.3495 = 2,296.31 grams (Round answer as needed)
2296 point 31 grams

The sum of two fractions is 8/9. the difference is 2/9. What are the two fractions?

Answers

The answer is 5/9 + 3/9, I got this by thinking, what equals 2/9? I came up with 5/9 and 3/9 so I tried and it was right
i think it would be 3/9+5/9

HELP PLEASE I WILL GIVE BEST ANSWERAngela is studying two types of birds. She measures the wingspan, in inches, of five Type 1 birds and five Type 2 birds.

What can she infer about the wingspans of the two types of birds?

Type 1: {18, 24, 20, 22, 26}
Type 2: {24, 21, 19, 26, 30}

A.
Type 1 and Type 2 birds have similar wingspan distributions.

B.
Type 1 and Type 2 birds have somewhat similar wingspan distributions.

C.
Type 1 birds and Type 2 birds do not have similar wingspan distributions.

D.
Type 1 birds and Type 2 birds have identical wingspan distributions.

Answers

Answer:

Step-by-step explanation:

The given data set for type 1 of birds is:

Type 1: {18, 24, 20, 22, 26}

Type 2: {24, 21, 19, 26, 30}

Mean of the type 1 data is:

Mean=(18+24+20+22+26)/(5)=(110)/(5)=22

Data                                                         (x-{\overline{x})^2

18                                                                    16

24                                                                   4

20                                                                   4

22                                                                   0

26                                                                   16

Now, mean average of squares is:

m=(40)/(5)=8

Standard deviation=SD=√(8)=2.828

Now, the difference of mean and its standard deviation of type 1 data set is:

=22-2.828

Difference =19.172  

The given data set for type 2 of birds is:

Type 2: {24, 21, 19, 26, 30}

Mean of the type 2 data is:

Mean=(24+21+19+26+30)/(5)=(120)/(5)=24

Data                                                        (x-{\overline{x})^2

24                                                                     0

21                                                                      9

19                                                                     25

26                                                                     4

30                                                                    36

Now, mean average of squares is:

m=(74)/(5)

m=14.8

Standard deviation=SD=√(14.8)=3.84

Now, the difference of mean and its standard deviation of type 2 data set is:

=24-3.84

Difference=20.16

Since, the difference of mean and standard deviation of both type 1 and type 2 data set is different, therefore, Type 1 birds and Type 2 birds do not have similar wingspan distributions.

Hence, option C is correct.

Answer:

Type 1 and Type 2 birds have similar wingspan distributions.

Step-by-step explanation:

there are 52 weeks in 1 year. In the space at the right, make a table and write a function rule relating the number of weeks to the number of years for 1,2,3, and n years. Then find Hana's age in weeks if she is 11 years old.

Answers

Given:
52 weeks in a year
Hana's age: 11 years

Find her age in weeks.

f(x) = 52x ; where x is the number of years.

f(11) = 52(11)
f(11) = 572 weeks

Hana is 572 weeks old.

Answer:

1o

Step-by-step explanation:

A square dinner napkin 8in. on each side is folded along its diagonal. Find the area of the folded napkin.

Answers

Since you need to find the area of a square napkin, you need to know what the formula for a square is. It is height multiplied by base. So a square is equal in all sides. 8×8=64
Answer: 64 in²
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