A truck on a straight road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 20.0 m/s. Then the truck travels for 20.0 s at constant speed until the brakes are applied, stopping the truck in a uniform manner in an additional 5.00 s. (a) How long is the truck in motion? (b) What is the average velocity of the truck for the motion described?
Answers
V_xf = V_xi + a_x(t)
V_xf = 20.0m/s
V_xi = 0m/s
ax = 2.0t
Thus, solve for t and get 10secondsand then take 5 seconds to break after 20 seconds of drivingso for
a) 10 + 20 + 5 = 35 seconds
for part b)
You can use the formula
Delta x/Delta t = average velocity
Need to find xf, knowing xi = 0
Thus, use the formula
x_f = x_i + V_xi(t) + (1/2)a_x(t)^(2)
x_f = 0 + 0(10) + (1/2)(2.0)(10)^(2)
x_f = 100m
so for the first 10 seconds the truck traveled 100msAt a speed of 20m/s
20m/s = xm/20s20*20 = x
x = 400
thus we have 100+400 = 500mthen it slows down from 500m to x_f
thus I use the equation
x_f = x_i + (1/2)(V_xf + V_xi)t
x_f = 500 + (1/2)(0 + 20)(5)x_f = 500 + 50
x_f = 550
therefore the total distance traveled is 550m
to calculate average velocity
550/35 = 16m/s
thusV_xavg = 16m/s
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The kinetic energy of the object with a mass of 2kg has a linear momentum of 6kgm/s is 9 joules.
What is kinetic energy?
Kinetic energy is the energy obtained when the body is in motion. It is obtained from the product of mass and velocity. The SI unit of Kinetic energy is Joule(J).
K.E = 1/2 (mv²) where m is the mass of the object and its unit is the kilogram. v is the velocity of the object and its unit is m/s. The momentum of the object is obtained from the product of mass and velocity.
From the given,
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Linear momentum (p) = m×v (m = mass of the object, v= velocity of the object)
v = p / m
= 6 / 2
= 3 m/s
The velocity of the object = 3 m/s
Kinetic energy = 1/2 (mv²)
K.E = 1/2 (2×3×3)
= 9 joules
Thus the kinetic energy of the object is 9 joules (J).
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Answer:
Chemical engineers develop and design chemical manufacturing processes. They apply the principles of chemistry, biology, physics, and math to answer problems that involve the production of chemicals, fuel, drugs, food, and many products
Explanation:
Answer:
The main role of chemical engineers is to design and troubleshoot processes for the production of chemicals, fuels, foods, pharmaceuticals, and biologicals, just to name a few. They are most often employed by large-scale manufacturing plants to maximize productivity and product quality while minimizing costs
Explanation:
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Physical quantities that exhibit both magnitude and direction are referred to as vector quantities. As an illustration, consider displacement, force, torque, momentum, acceleration, and velocity.
Typically, an arrow is used on top of a vector quantity to depict the vector value of the velocity and to clarify that the quantity has both magnitude and direction.
A quantity with both magnitude and direction is referred to as a vector. A unit vector is one with a magnitude of 1. It also goes by the name Direction Vector.
Given vector is :
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and the other vector is :
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The unit vector along is
Hence, component of A vector along B vector is =
=
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3^2 + 4^2 = 5^2
Therefore, the hypotenuse has a magnitude of 5
Answers
Use the formula:
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r = separatioon
k = constant = 9x10^9 in MKS units
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r = sqrt[k q1 q2/F]
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r = 0.0302 m
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