Chords and arcs.

find x​
chords and arcs. find x​ - 1

Answers

Answer 1
Answer:

The chords SR and ST are congruent, so the (minor) arcs SR and ST have the same measure.

The measure of the arcs SR, ST, and RT add up to 360º. So we have

2xº + 64º = 360º  ==>  x = 148


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Find the value of x that will make A||B 4x 3x+10 x=

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Answers

0.5477225575 ... u have to change this in scientific notation

Question 8A rectangle has vertices at (0,0), (3,0), and (0,6). What is the area
of the rectangle?

I’ll mark you!

Answers

Answer:

18 square units

Step-by-step explanation:

The area of a rectangle is simply it's base length multiplied by its height.

A = b × h

Since a rectangle has all right angles, it must have two sets of parallel sides.

Given the coordinates (0, 0), (3, 0), (0, 6) which are vertices of the rectangle. You can find the distance between each point to get the side length and then multiply the two side lengths together.

The number of text messages sent by 25 13-year-olds over the past month are as follows791 542 671 672 555 582 616 961 639
691 648 967 959 826 573 598 790 954
711 515 649 960 949 802 507
a. Construct the frequency distribution using classes of 500 up to 600, 600 up to 700, etc.
Texts Frequency
500 up to 600
600 up to 700
700 up to 800
800 up to 900
900 up to 1000
Total
b. Construct the relative frequency distribution, the cumulative frequency distribution and the cumulative relative frequency distribution. (Round "Relative Frequency" and "Cumulative Relative Frequency" to 2 decimal places.)
Texts Relative Frequency Cumulative Frequency Cumulative Relative Frequency
500 up to 600
600 up to 700
700 up to 800
800 up to 900
900 up to 1000
c-1. How many of the 13-year-olds sent at least 600 but less than 700 text messages?
c-1. Number of 13-year-olds
Number of 13-year-olds
c-2. How many sent less than 900 text messages?
Number of 13-year-olds
d-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? (Round your answer to the nearest whole percent.)
Percent of 13-year-olds %
d-5. What percent of the 13-year-olds sent less than 600 text messages? (Round your answer to the nearest whole percent.)
Percent of 13-year-olds %

Answers

Answer:

7 ; 19 ; 8% ; 28%

Step-by-step explanation:

Given the data:

791 542 671 672 555 582 616 961 639

691 648 967 959 826 573 598 790 954

711 515 649 960 949 802 507

How many of the 13-year-olds sent at least 600 but less than 700 text messages? = 7

c-2. How many sent less than 900 text messages? = (7 + 7 + 3 + 2) = 19

d-1. What percent of the 13-year-olds sent at least 800 but less than 900 text messages? =0.08 × 100 = 8% (from relative frequency)

d-5. What percent of the 13-year-olds sent less than 600 text messages?  0.28 × 100 = 28% (from relative frequency)

Final answer:

By sorting text messages into classes, we can get the frequency distribution. From there, we can determine the relative and cumulative frequencies. Finally, we can examine how many students sent texts within certain ranges and express these as percentages.

Explanation:

To answer this question, let's first classify the amount of text messages sent by each of the 25 13-year-olds into groups or classes of 100. Then we count the frequencies, or how many text messages fall into each class. This helps us construct the frequency distribution.

The classes are: 500-600, 600-700, 700-800, 800-900, and 900-1000.

Next, we calculate the relative frequency by dividing the frequency of each class by the total number of students. We round each relative frequency to 2 decimal places.

To calculate cumulative frequency, we keep an ongoing total of frequencies as we move up the classes. The cumulative relative frequency is computed similarly but applied to the relative frequencies.

In the last part, we determine how many 13-year-olds sent at least a certain number of texts but less than another number, and convert these to percentages.

Learn more about Frequency Distribution here:

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What does the expression (8x)2 represent

Answers

Option D is correct.

We have an expression that is used to calculate the area of a square - s^(2), where s is the side of the square.

We have to estimate the value of the expression(8x)^(2)

What is the area and perimeter of a square of side 'a' ?

The area of a square is - Area = a^(2) and the perimeter is - P  = 4a.

In the question, we have to estimate the value of the expression (8x)^(2).

Let f(x) = (8x)^(2)

The expression given to us is s^(2).

Let f(s) = s^(2)

Compare f(s) and f(x), you will get -

s = 8x

Hence, the expression (8x)^(2) represents the area of square with side length of 8x.

Hence, Option D is correct.

To solve more questions on squares, visit the link below -

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Answer:

option d

Step-by-step explanation:

please mark brainlist

While hiking, Sandra went up 120 meters. If Sandra started at 800 meters above sealevel, what is her elevation now?

Answers

The Answer:

If Sandra started at 800 meters and went up 120, the answer would be 920.

Step-by-step explanation:

First, simply add 800 meters, which is what she started with. Next, since she has gone up 120 meters since then, and the question is asking us what her elevation is NOW, you can add 800 + 120 to get 920. This question is solved by using addition.

Hope this helps!

Sandra is 920 meters above sea level


You would add 120 and 800 which is 920

PLEASE HELP!!!!!
will mark brainliest!!!!!

Answers

Answer:

fx =1; then fx =2; then fx =4

Step-by-step explanation:

then plug the coordinates in as x is horizontal bar in top right then the fx