What is the molarity of a solution made with 298g of potassium chloride dissolved in enough water to make 2L of solution?

The molarity of the solution made by dissolving 298 g of KCl in enough water to make 2 L of the solution is 2 M

• We'll begin by calculating the number of mole in 298 g of potassium chloride, KCl. This can be obtained as follow:

Mass of KCl = 298 g

Molar mass of KCl = 39 + 35.5 = 74.5 g/mol

Mole of KCl =?

Mole = mass / molar mass

Mole of KCl = 298 / 74.5

Mole of KCl = 4 moles

• Finally, we shall determine molarity of the KCl solution. This can be obtained as follow:

Mole of KCl = 4 moles

Volume = 2 L

Molarity of KCl =?

Molarity = mole / Volume

Molarity of KCl = 4 / 2

Molarity of KCl = 2 M

Therefore, the molarity of the KCl solution is 2 M.

Learn more: brainly.com/question/24256264

Answer:

2 M

Explanation:

The equation for molarity is "M = moles/liters"

Potassium chloride's atomic mass is 74.55, meaning one mole of KCl is equal to 74.55g. In the equation, 298g of KCl is being used. To find out how many moles this is, multiply 298g of KCl by (1 mol/74.55g of KCl) to get 4.0 moles. Now you can use the equation for molarity.

M = 4.0 moles/2 Liters